Assuming yo meant
4(3b+2)²=64
divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2
A is answer
I think the answer is 1,600 totals students taking metaphysics
Your answer will be twelve and nine thousandths because in place value decimals are like tenths, hundredths, thousandths. In place value for regular numbers are ones, tens, hundreds and so on. So, when you have 12.009, you are going to separate the decimals with the numbers. Then, write down the number in words which would be twelve. Now, go to the decimal and write that down, which is 9 thousandths. Finally, combine the both of them to get: twelve and nine thousandths.
Hope this helps :)
and good luck
Answer:
y = 12x+16
Step-by-step explanation:
Simplify both sides of the equation then isolate the variable.
Step 1, add 11 to both sides.
−1
/2
y+11+−11=6x+3+−11
−1
/2
y=6x−8
Step 2, divide both sides by (-1)/2.
You will be left with
y = 12x+16
Answer:
Step-by-step explanation:
The distance the light traveled to the ground is the range of the plane expressed as:
R = U*√2H/g
U is he velocity
H is the max height
g is the acc. due to gravity
Let us get U first using the formula
H = u²sin²Ф/2g
1000 = u²sin²60/2(9.81)
1000*19.62 = 0.8660u²
19620 = 0.8660u²
u² = 19620/0.8660
u² = 22655.88
u = √22655.88
u = 150.52m/s
Next is to get the range
R = 150.52√2(1000)/9.81
R = 150.52 √2000/9.81
R = 150.52√203.87
R = 150.52*14.28
R = 2149.16m
Hence the distance the light traveled to the ground is 2,149.16m
