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vichka [17]
2 years ago
9

To convert a measurement, Pete must move the decimal point to the left 4 places. This a shortcut for the operation. which operat

ion is he using? Which power of 10 is involved?
Mathematics
2 answers:
ASHA 777 [7]2 years ago
8 0
<span>The moving of decimal to the left is a shortcut to the operation of multiplying number by decimal numbers. So the power of 10 that is involved in converting the measurements of pete is -4, so he needs to multiply the measurement by 10^-4 to convert it.</span>
lutik1710 [3]2 years ago
6 0

Answer: Because he moved the decimal 4 places to the left, Pete is dividing by 10 to the 4th power, or 10,000.

Step-by-step explanation:

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we are given

a=f(t)=2t^2

we can use average rate of change formula from t=a to t=b

A=\frac{f(b)-f(a)}{b-a}

Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

6 0
2 years ago
Julie gathered data about the numbers of pages and chapters in several books by her favorite author.The equation of the line of
erica [24]

Answer:

C

Step-by-step explanation:

To get the approximate number of pages in the chapters, what we need to do is to substitute for the value of x in the line of best fit equation.

Thus, we have;

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7 0
2 years ago
Read 2 more answers
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
Because you are working a late shift, you will get an increase in your wage. You will get and additional 10% per hour from 6:00p
siniylev [52]

CHECK THE COMPLETE QUESTION BELOW:

Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hour from 6:00 PM to 12:00 AM and additional 15% from 12:00 AM to 1:00 AM." Employee: "I am working from 2:00 PM to 12:00 AM. Between 2:00 PM and 6:00 PM, I will make $12.00 per hour. Between 6:00 PM and 12:00 AM, I will make __________ per hour

Answer:

I will make $13.2 per hour

Explanation:

It can be deducted from the question that that the money Employee gets money for Working from 2.00 PM to 6.00 PM = $12per hour

Also the Employee gets additional 10% of money for working from 6.00 PM to 12.00 AM which implies that

10% = (10/100)*$12per hour

=$1.2per hour

Again, Employee gets additional 15% of the money for working from 12.00 AM to 01.00 AM which can be calculated as:

15% = (15/100)*$12per hour

=$1.8 per hour

which means that Employee gets additional $1.8 per hour

of the money for working from 12.00 AM to 01.00 AM

Therefore, if Employee works from 2.00 PM to 12.00 AM,

Employee will gets money for Working from 2.00 PM to 6.00 PM as well as the 10\% extra wage which

= $12 + $1.2 = $13.2

= \$ 12 + \$ 1.2 = \$ 13.2

7 0
2 years ago
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Harlamova29_29 [7]
Applying the rule for dilation, we will multiply the scale factor to its coordinates. 
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x = (.5)(0) = 0
y = (.5)(2) = 1

Therefore coordinates of Q' is (0,1) 

*Having a scale factor of >1, the figure is said to be reduced. 
8 0
2 years ago
Read 2 more answers
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