10 of those sheets are secondary colors.
40% = 0.4
0.4(25) = 10
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
This problem is an Arithmetic Sequence
where
the first term is 
and
the common difference is 
In general we can write an Arithmetic Sequence as a rule

where
a1 is the first term
d is the common difference
so

<u>Find the term a7</u>
![an=a1+d*(n-1)\\ \\ a7=23+(-2)*[7-1]\\ \\\\ a7=23-12\\ \\\\ a7=11](https://tex.z-dn.net/?f=%20an%3Da1%2Bd%2A%28n-1%29%5C%5C%20%5C%5C%20%20a7%3D23%2B%28-2%29%2A%5B7-1%5D%5C%5C%20%5C%5C%5C%5C%20a7%3D23-12%5C%5C%20%5C%5C%5C%5C%20%20%20%20a7%3D11%20%20%20%20%20)
therefore
<u>the answer is</u>

Answer:
Step-by-step explanation:
From the given information:
Let X represent the amount of the stock that goes up in the first period; &
Let Y denote the cumulative amount that goes up in the first three periods.
Then,




∴

Addends are any of the numbers added together in an equation.
The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations.
For ex:
2 - (8 + 3) here, the 8 and 3 have to be grouped together before doing the subtraction.
Any addition problem without parentheses can be used for one where the grouping doesn't matter
Answer:
Original sum of money = $2246.51
Step-by-step explanation:
Interest = $96.60
Interest is compounded 6 times in a year ; n = 6
time = 1 year ; Rate of interest (r) = 4.2%
Interest = Future Value - Principal Value ...........(1)
![\text{Future Value = }Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}\\\\\text{Substituting this value in equation (1) , We get }\\\\Interest=Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}-Principal\\\\\implies 96.60=Principal[\cdot (1+\frac{4.2}{100\times 6})^{6\cdot 1}-1]\\\\\implies Principal=\$2246.51](https://tex.z-dn.net/?f=%5Ctext%7BFuture%20Value%20%3D%20%7DPrincipal%5Ccdot%20%281%2B%5Cfrac%7Br%7D%7B100%5Ctimes%20n%7D%29%5E%7Bn%5Ccdot%20t%7D%5C%5C%5C%5C%5Ctext%7BSubstituting%20this%20value%20in%20equation%20%281%29%20%2C%20We%20get%20%7D%5C%5C%5C%5CInterest%3DPrincipal%5Ccdot%20%281%2B%5Cfrac%7Br%7D%7B100%5Ctimes%20n%7D%29%5E%7Bn%5Ccdot%20t%7D-Principal%5C%5C%5C%5C%5Cimplies%2096.60%3DPrincipal%5B%5Ccdot%20%281%2B%5Cfrac%7B4.2%7D%7B100%5Ctimes%206%7D%29%5E%7B6%5Ccdot%201%7D-1%5D%5C%5C%5C%5C%5Cimplies%20Principal%3D%5C%242246.51)
Hence, the original sum of money borrowed = $2246.51