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2 years ago

Next no. in the sequence 7 2 0 7 8 4 3

Mathematics

2 answers:

Andreas93 [3]2 years ago

4 0

7,2,0,7,8,4,3... in this order?

lozanna [386]2 years ago

3 0

Any more information?

This is not an arithmetic or geometric sequence. It has no constant velocity, acceleration, or even thrust. You COULD make a higher order function fit each data point, however until you can actually find a constant rate of change at the higher orders it is not certain in any way that that function would predict the next term...

dy/dx=-5, -2, 7, 1, -4, -1
d2y/dx2=3, 9, -6, -5, 3
d3y/dx3=6, -15, 1, 8
d4y/dx4=-21, 16, 7
d5y/dx5=37, -9
d6y/dx6=-46 *note that the data never showed a constant rate of change

From above it can be seen that we COULD create a function to fit all of the points, but there would be no certainty in any way that that function would accurately predict the next number in the sequence.

ax^6+bx^5+cx^4+dx^3+ex^2+fx+g=y

And that would be a tedious amount of work to create that matrix to find a function that is essentially useless in predicting the next number in the sequence with any certainty...

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Answer:

<em>96π units²</em>

Step-by-step explanation:

Find the diagram attached

Area of a sector is expressed as;

Area of a sector = θ/2π * πr²

Given

θ = 3π/4

r = 16

Substitute into the formula

area of the sector = (3π/4)/2π * π(16)²

area of the sector = 3π/8π * 256π

area of the sector = 3/8 * 256π

area of the sector = 3 * 32π

<em>area of the sector =96π units²</em>

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Answer:

There are 20 vegetable plants in garden.

Step-by-step explanation:

We are given the following in the question:

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Percentage of vegetable = 40%

Number of plants in garden = 50

Number of vegetables in garden =

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Number of flowers in garden =

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If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le

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Answer:

$4\sqrt{\pi}$

Step-by-step explanation:

The cross section of a sphere is a circle with area $\pi r^2$ , where radius is given as 4
The cross section of the cube is a square with area $a^2$ , where a is side length of square

The circle area = the square area. Thus we have:

$\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}$

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Answer:

Answer: 5/12 or approx. 0.42

Step-by-step explanation:

The ball will displace as much water as its volume.

Meaning, the volume of the ball and the volume of the increase in water in the barrel will be equal.

Volume of a sphere:

$V_s=\frac{4}{3} \pi r^3$

The radius is half the diameter. The diameter of the sphere is 10, thus:

$r = d/2 = 10/2 = 5$

5^3 = 5*5*5 = 25*5 = 125

$V_s=\frac{4}{3} \pi * 5^3=\frac{4}{3} \pi * 125$

The volume of a cylinder, which will be the shape of the increase in water, is the following:

$V_c=\pi r^2 h$

We know the radius r, as we know the diameter.

$r=d/2=40/2=20$

$V_c=\pi r^2 h=\pi h * 20^2 = \pi h * 400$

We are looking for the height of the cylinder, h, as that will be the height of the water rise.

Since we know these 2 volumes are the same, we'll set them equal to each other and solve the equation:

$V_s = V_c$

$\frac{4}{3} * 125 * \pi = 400 * h * \pi$

We can get rid of pi by dividing both sides by pi:

$\frac{4}{3} * 125 = 400 * h$

And now divide both sides by 400:

$\frac{4}{3} * \frac{125}{400}= h$

Just reversing it and putting h to the left:

$h = \frac{4}{3} * \frac{125}{400} = \frac{4 * 125}{3 * 400}$

I see that I can divide both the numerator and the denominator by 4:

$h =\frac{125}{3 * 100}= \frac{125}{300}$

I'll now divide both the numerator and the denominator by 25 to simplify the expression:

$h=\frac{125}{300} =\frac{125 / 25}{300 / 25} = \frac{5}{12}$

Answer: The water rises by 5/12 (five twelfths).

If I want an approximate decimal answer, I can simply run this expression in a calculator:

$\frac{5}{12}$ ≈ $0.416666667$ ≈ $0.42$

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Answer:

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