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1 year ago

Next no. in the sequence 7 2 0 7 8 4 3

Mathematics

2 answers:

Andreas93 [3]1 year ago

4 0

7,2,0,7,8,4,3... in this order?

lozanna [386]1 year ago

3 0

Any more information?

This is not an arithmetic or geometric sequence. It has no constant velocity, acceleration, or even thrust. You COULD make a higher order function fit each data point, however until you can actually find a constant rate of change at the higher orders it is not certain in any way that that function would predict the next term...

dy/dx=-5, -2, 7, 1, -4, -1
d2y/dx2=3, 9, -6, -5, 3
d3y/dx3=6, -15, 1, 8
d4y/dx4=-21, 16, 7
d5y/dx5=37, -9
d6y/dx6=-46 *note that the data never showed a constant rate of change

From above it can be seen that we COULD create a function to fit all of the points, but there would be no certainty in any way that that function would accurately predict the next number in the sequence.

ax^6+bx^5+cx^4+dx^3+ex^2+fx+g=y

And that would be a tedious amount of work to create that matrix to find a function that is essentially useless in predicting the next number in the sequence with any certainty...

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Alexeev081 [22]

so the answer is 36.

Hope this will help u...

7 0

1 year ago

Read 2 more answers

Which term in the arithmetic sequence 11, 4,-3 . . . is -129?

telo118 [61]

Answer:

23rd term

Step-by-step explanation:

Plz mark as Brainliest!

4 0

2 years ago

The diagram shows some land in the shape of a quadrilateral ABCD. AB = 6 km, AD = 5 km and CD = 12 km Angle BAC = 30 The land is

Goshia [24]

Answer:

£495 million

Step-by-step explanation:

To find out the total cost of the land, we need to first calculate the area of the land.

Step 1: Find area of right angled triangle ADC

AD = 5 km,

DC = 12 km

Area of the right triangle = ½*a*b

a = 5km

b = 12km

Area = ½*5*12

= 5*6

Area of ADC = 30 km²

Step 2: Find the area of triangle ABC

First, let's find the length of AC using Pythagorean theorem

AC² = AD² + DC²

AC² = 5² + 12² = 25 + 144

AC = √169

AC = 13km

Area of ∆ABC = ½*AB*AC*sin(30°)

= ½*6*13*0.5

= 3*13*0.5

Area of ∆ABC = 19.5 km²

Total area of the land = area of ∆ADC + ∆ABC = 30 + 19.5 = 49.5 km²

Step 3: calculate how much the land costs

If the land costs £10 million per km²,

Cost of 49.5 km² = 49.5 × 10 = £495 million

4 0

2 years ago

Tonyas dog walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. beth does not charge

andreev551 [17]

Answer:

Step-by-step explanation:

given that tonya charges 20$ monthly fee and 3$ per mile of her dog-walking service.

and beth does not charge any monthly fee but charges 5$ per mile of the dog walked in.

let x be the number of miles dog has walked in a month.

the amount tonya will charge on x miles = fixed monthly fee + number of miles * charge per mile = 20+3x

and the amount beth will charge on x miles = 0+ 5*x = 5x.

we are asked to find the x-value for which beth chargeable amount = tonya chargeable amount

that is 5x = 20+3x

5x-2x = 20

2x=20

x= $\frac{20}{2} = 10$

hence number of miles for which tonya and beth will charge the same amount is 10.

7 0

2 years ago

Ben swims 50,000 yards per week in his practices. Given this amount of training, he will swim the 100-yard butterfly in 51.5

Elanso [62]

Answer:

MArginal productivity: $\frac{dt}{dL}=-0.0002$

We can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

$\frac{dt}{dL}$

where dt is the variation in time and dL is the variation in training yards.

We can not derive the function because it is not defined, but we can approximate with the last two points given:

$\frac{dt}{dL}\approx\frac{\Delta t}{\Delta L} =\frac{t_2-t_1}{L_2-L_1}=\frac{44.6-46.4}{70,000-60,000}=\frac{-2.0}{10,000}=-0.0002$

Then we can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.

6 0

1 year ago