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2 years ago

Nadia built a robot to filter air and water efficiently. She expects the robot to filter more than 343 liters of

Mathematics

1 answer:

Natasha2012 [34]2 years ago

7 0

Answer:

The correct option is;

B. The robot filters the expected amount of air and water, but it doesn't use the expected amount of energy

Step-by-step explanation:

The given requirements are;

Volume of air and water to be filtered by the robot = 343 liters

The amount of energy consumed by the robot < 49 joules

The number of minutes the robot filters air and water to filter more than 343 liters = 12A + 8W > 343

The number of minutes the robot filters air and with less than 49 Joule of energy = 3A + 4W < 49

Given that filtering air takes 20 minutes, filtering water takes 15 minutes, we have;

To filter more than 343 liters, we have

12*20 + 8*15 = 360 > 343

The robot meets the amount of air and water requirement

To filter with less than 49 joules we have

3*20 + 4*15 = 120 > 49

Therefore, the robot does not meet the energy requirement

The correct option is the robot filters the expected amount of air and water, but it doesn't use the expected amount of energy.

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Sammy has a 10-foot ladder, which he needs to climb to reach the roof of his house. the roof is 12 feet above the ground. the ba

timama [110]

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2 years ago

Suppose that you bet $5 on each of a sequence of 50 independent fair games. Use the central limit theorem to approximate the pro

amm1812

Answer:

chances chances of happening = 0.0119

Step-by-step explanation:

given data

bet = $5

independent fair games = 50

solution

we will think game as the normal distribution

so here mean is will be

mean = $\frac{50}{2}$

mean = 25

and standard deviation will be

standard deviation = $\sqrt{50*0.5*0.5}$

standard deviation = 3.536

we have to lose 33 out of 50 time for lose more than $75

so as chance of doing things z score is

z score = $\frac{33-25}{3.536}$

z score = 2.26

so from z table

chances chances of this happening = 0.0119

8 0

2 years ago

Anna set up a lemonade stand on her block over the summer. She recorded each day’s high temperature and the number of cups of le

Alexxx [7]

Answer:

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

Step-by-step explanation:

We are given a linear regression model that relates daily high temperature, in degrees Fahrenheit and number of lemonade cups sold.

$y = -34+ \frac{3}{5} x$

Where y is the number of cups sold and x is the daily temperature in Fahrenheit.

Residual value:

A residual value basically shows the position of a data point with respect to the regression line.

A residual value of 0 is desired which means that the regression line best fits the data.

The Residual value is calculated by

Residual = Observed value - Predicted value

The predicted value of number of lemonade cups is obtained as

$y = -34+ \frac{3}{5} (95)\\\\y = -34+ 3 (19)\\\\y = -34+ 57\\\\y = 23$

So the predicted value of number of lemonade cups is 23 and the observed value is 21 so the residual value is

Residual = Observed value - Predicted value

Residual = 21 - 23

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

7 0

2 years ago

The 8th term of a GP is -7/32 find its common ratio if its first term is 28

Ugo [173]

<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

$\text{8}^{th}$ term of a Geometric progression is given as $\dfrac{-7}{32}$ . The first term is given as $28$ .

Any general Geometric progression can be represented using the series $a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}$ .

The first term in such a GP is given by $a$ , common ratio by $r$ , and the $n^{th}$ term is given by $ar^{n-1}$ .

In the given GP, $a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}$

∴ Common ratio is $\dfrac{-1}{2}$ .

5 0

2 years ago

Which number has the lowest value ?<br>a) 1/2 +0.30 b) 0.10 + 3/4 c) 1/3 + 0.50 d) 1/3 +0.40<br>

Leto [7]

Hey!

-------------------------------

Let's Solve A:

1/2 = 0.5

0.5 + 0.30 = 0.80

a = 0.80

-------------------------------

Let's Solve B:

3/4 = 0.75

0.10 + 0.75 = 0.85

b = 0.85

-------------------------------

Let's Solve C:

1/3 ≈ 0.33

0.33 + 0.50 = 0.83

c = 0.83

-------------------------------

Let's Solve D:

1/3 ≈ 0.33

0.33 + 0.40 = 0.73

d = 0.73

-------------------------------

Answer:

By solving each equation we can see that option A has the lowest value!

-------------------------------

Hope This Helped! Good Luck!

8 0

2 years ago