Answer:
Part a) The exterior surface area is equal to 
Part b) The volume is equal to 
Part c) The volume water left in the trough will be 
Step-by-step explanation:
Part a) we know that
The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles
so
<em>Find the area of two rectangles</em>
![A=2[12*5]=120\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B12%2A5%5D%3D120%5C%20ft%5E%7B2%7D)
<em>Find the area of two trapezoids</em>
![A=2[\frac{1}{2}(8+2)h]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29h%5D)
Applying Pythagoras theorem calculate the height h



substitute the value of h to find the area
![A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29%284%29%5D%3D40%5C%20ft%5E%7B2%7D)
The exterior surface area is equal to

Part b) Find the volume
We know that
The volume is equal to

where
B is the area of the trapezoidal face
L is the length of the trough
we have


substitute

Part c)
<em>step 1</em>
Calculate the area of the trapezoid for h=2 ft (the half)
the length of the midsegment of the trapezoid is (8+2)/2=5 ft

<em>step 2</em>
Find the volume
The volume is equal to

where
B is the area of the trapezoidal face
L is the length of the trough
we have


substitute
