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vredina [299]
2 years ago
13

The image shows a ray of light bending at the boundary of a glass block. According to a law of optics, = n, where n is a constan

t. Which equation states the same law in terms of a and b?

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0
The formula for the light bend would be n1*sin i= n2 * sin r

If you use "sin (90-x)= cos x" principle, you can change the sin in the equation into
n1*sin i= n2 * sin r
n1 * cos a= n2 * cos b
n2/n1= cos a/ cos b

Assuming the n constant is the ratio of the glass compared to water then the answer would be: cos a/ cos b
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If EBC = 31a - 2 and EBH = 4a + 45 find HBC
Zigmanuir [339]

Answer:

The measure of angle HBC is m∠HBC=61°

Step-by-step explanation:

In this problem we have that

The line BH bisects angle EBC,

see the attached figure to better understand the problem

then

m∠EBC=m∠EBH+m∠HBC

m∠EBH=m∠HBC

so

m∠EBC=2(m∠EBH)

substitute the given values and solve for a

31a-2=2(4a+45)\\31a-2=8a+90\\31a-8a=92\\23a=92\\a=4

<em>Find the measure of angle EBH</em>

m∠EBH=(4(4)+45)=61°

Remember that

m∠EBH=m∠HBC

therefore

The measure of angle HBC is m∠HBC=61°

8 0
2 years ago
At a large conference of teachers from a variety of subjects, a random sample of 50 mathematics teachers attending the conferenc
melamori03 [73]

Answer:

C. All mathematics teachers who have taken one or more courses in statistics

5 0
2 years ago
Which of the following is the expansion of (3c + d2)6?
vovangra [49]

Answer: Option A) 729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12} is the correct expansion.

Explanation:

on applying binomial theorem,  (a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r

Here a=3c, b=d^2 and n=6,

Thus, (3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r

⇒ (3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6

⇒(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}

⇒(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}

⇒(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}

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2 years ago
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The answer is 20 percent
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2. The ground below your feet moves at the rate at which
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I’m just going off of what I was told in fifth grade, and we were told it was finger nails. Hope this helps!
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