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Neko [114]
2 years ago
13

16.A guidance counselor is planning schedules for 30 students. Sixteen students say they want to take French, 16 want to take Sp

anish, and 11 want to take Latin. Five say they want to take both French and Latin, and of these, 3 wanted to take Spanish as well. Five want only Latin, and 8 want only Spanish. How many students want French only?

Mathematics
2 answers:
MariettaO [177]2 years ago
8 0

Answer:7

Step-by-step explanation:

This can be solved by Venn-diagram

Given there  are total 5 students who want french and Latin

also 3 among them want Spanish,french & Latin

i.e. only 2 students wants both french and Latin only.

Also Student who want only Latin is 5

Thus Student who wants Latin and Spanish both only is 11-5-3-2=1

Students who want only Spanish is 8 Thus students who wants Spanish and French is 4

Similarly Students who wants Only French is 16-4-3-2=7

Guest1 year ago
0 0

French only
6

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Answer:

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Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

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Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

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2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
2 years ago
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Answer:

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