The artistic crop isn't helpful; it cuts off some vertex names.
The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so
EH² = HL² + EL²
EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339
Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.
Answer: 4.25
f(x) = 
note the range is {1, 5, 25, 125 } which can be expressed as
{ 
, 
, 
, 
}
the exponents being the domain { 0, 1, 2, 3 }
thus f(x) = an exponential function
Answer:
On the first hour she gathered 8 mushroons, on the second 15 mushroons and on the third she gathered 14 mushroons.
Step-by-step explanation:
Helen gathred a total of 37 mushroons in three hours. On the first hour she gathered "x" mushroons, on the second hour she gathered "x + 7" mushroons and on the third hour she gathered "x + 6". Therefore the sum of mushrrons she gathered on each hour should be equal to the total she gathered as shown below:
37 = x + (x+ 7) + (x + 6)
37 = 3*x + 13
3*x + 13 = 37
3*x = 37 - 13
3*x = 24
x = 24 / 3
x = 8
On the first hour she gathered 8 mushroons, on the second 15 mushroons and on the third she gathered 14 mushroons.
Answer:
Step-by-step explanation:
For the null hypothesis,
H0 : p = 0.63
For the alternative hypothesis,
Ha : p < 0.63
This is a left tailed test
Considering the population proportion, probability of success, p = 0.63
q = probability of failure = 1 - p
q = 1 - 0.63 = 0.37
Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 478
n = number of samples = 800
P = 478/800 = 0.6
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76
From the normal distribution table, the area below the test z score in the left tail 0.039
Thus
p = 0.039
