All categories

2 years ago

During a sale, 20-cent candy bars were sold at 3 for 50 cents. How much is saved on 9 bars?

Mathematics

1 answer:

Mazyrski [523]2 years ago

8 0

Answer:

Step-by-step explanation:

$0.30

Step-by-step explanation:

1 bar of candy = $0.20

3 bars of candy = $0.50

To solve, multiply for both:

If you pay for each candy bar individually, they each cost $0.20. Multiply 9 with 0.20:

9 x 0.20 = $1.80

If you pay for the candy bars by 3's, they cost $0.50 each pack. Divide 9 with 3, then multiply by 0.50:

9/3 = 3

3 x 0.50 = $1.50

Subtract the total cost of the individual from the pack:

$1.80 - $1.50 = $0.30

. $0.30 is your answer.

You might be interested in

The tables show the relationships between x and y for two data sets. Data Set Data Set I X 5.5 1 Z 11.0 2 10 5 165 3 15 220 2D 5

notka56 [123]

Answer:

C I beleive the answer is C Both data sets show multiplicative relationships.

In Data Set I, y is 5.5 times x, and in Data Set II, y is 5 times x.

Step-by-step explanation:

I beleive the answer it C thank you bye bye have a nice day hope this helped

5 0

1 year ago

Read 2 more answers

Which expression is equivalent to (StartFraction 125 squared Over 125 Superscript four-thirds Baseline EndFraction? StartFractio

stealth61 [152]

Answer:

$\frac{125^2}{125^\frac{4}{3}} = 25$

Step-by-step explanation:

Given

$\frac{125^2}{125^\frac{4}{3}}$

Required

Find an equivalent expression

$\frac{125^2}{125^\frac{4}{3}}$

Apply the following law of indices;

$\frac{a^m}{a^n} a^{m-n}$

The expression becomes

$125^{2-\frac{4}{3}}$

Solve the exponents

$125^{\frac{6-4}{3}}$

$125^{\frac{2}{3}}$

Express 125 as 5³

$5^{3^*\frac{2}{3}}$

Solve the exponents

$5^2$

$25$

Hence;

$\frac{125^2}{125^\frac{4}{3}} = 25$

5 0

2 years ago

Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang

PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx = 2x

since d(fx))/dx = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0

1 year ago

Read 2 more answers

Miriam is visiting five friends in her neighborhood, Louise, Mike, Nicole, Oscar, and Pascal. In each arrangement below, the fir

Advocard [28]

If N is first and L is last, then we just need to find all of the permutations for M, O, and P

with first letter M: MOP MPO

with first letter O: OPM OMP

with first letter P: PMO POM

Now, place the N in front and the L at the end of each permutation. There are 6 permutations in total:

NMOPL NMPOL

NOPML NOMPL

NPMOL NPOML

4 0

2 years ago

Read 2 more answers

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$

and we found the distance PQ and QA

; $d_{PQ}=\sqrt{125}$ , $d_{QA}=12$

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0

1 year ago