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Lerok [7]
2 years ago
10

Jeremiah and Tristan work at a dry cleaners ironing shirts. Jeremiah can iron 35 shirts per hour, and Tristan can iron 20 shirts

per hour. Jeremiah and Tristan worked a combined 17 hours and ironed 490 shirts. Determine the number of hours Jeremiah worked and the number of hours Tristan worked.
Mathematics
1 answer:
laiz [17]2 years ago
5 0

The number of hours Jeremiah ironed = 10 hours

The number of hours Tristan ironed = 7 hours

<u>Step-by-step explanation</u>:

  • Jeremiah can iron = 35 shirts per hour
  • Tristan can iron = 20 shirts per hour
  • Total work done by both = 490 shirts

Let 'x' be the number of hours Jeremiah ironed.

Let 'y' be the number of hours Tristan ironed.

x+y = 17   ------(1)

35x + 20y = 490  -------(2)

Multiply (1) by 20 and subtract (2) from (1),

 20x + 20y = 340

-(<u>35x + 20y = 490</u>)

 <u>-15x         = -150 </u>

x = 150/15

x = 10

Substitute x=10 in (1)

10+y = 17

y = 7

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Two cells are viewed and measured under a microscope. The approximate diameter
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Answer:

option D. 4.7 x 10-4 m

Step-by-step explanation:

<u><em>The correct question is</em></u>

• cell P: 5.0 x 10-4 meters

• cell Q: 3.0 x 10-5 meters

we have            

The diameter of cell P is  5*10^{-4}\ m

The diameter of cell Q is  3*10^{-5}\ m

Rewrite the diameter of cell P as    

5*10^{-4}\ m=5*10^{-4}(\frac{10}{10})=50*10^{-5}\ m

Find the difference

50*10^{-5}\ m-3*10^{-5}\ m=47*10^{-5}\ m

Rewrite the difference as

47*10^{-5}\ m=47*10^{-5}}(\frac{10}{10})=4.7*10^{-4}\ m

7 0
2 years ago
robin is making bead necklaces she want to use 717 beads to make 57 necklaces. if she wants each necklaces to have the same numb
EleoNora [17]

717=12\cdot684+33

<u>33 beads</u>

7 0
2 years ago
Terrence buys a new car for $20,000. The value of the car depreciates by 15% each year. If f(x) represents the value of the car
Lerok [7]

Answer

The function represents the car’s value after x years.

f(x) = 20,000(0.85)x

Reason

As given

Terrence buys a new car for $20,000.

The value of the car depreciates by 15% each year.

15 % is written in the decimal form

= \frac{15}{100}

= 0.15

Thus

The decrease in the value of car is represented by = a (1 - r)× t

Where a is the original cost

r is the depreciates rate in decimal form

t is time in years.

Here a = $20000 ,r = 0.15 , t = x years

The value of car after x years = 20,000 (1 -0.15)x

                                                 = 20000(0.85)x

Therefore the the value of the car after x years is represented by  f(x) = 20,000(0.85)x .

4 0
2 years ago
Read 2 more answers
PLEASE HELP! A horse-drawn carriage tour company has found that the number of people that take their tour depends on the price c
Natasha_Volkova [10]
A is the correct answers       
8 0
2 years ago
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
2 years ago
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