Answer:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation
And replacing we got:
So then the sample proportion of bare ground spots is 0.792 for this sample
Step-by-step explanation:
We have the following info given from the problem:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation)
And for this case if we want to find the sample proportion of bare ground spots we can use this formula:
And replacing we got:
So then the sample proportion of bare ground spots is 0.792 for this sample
Answer:
Hybrid basis
Step-by-step explanation:
There are different methods of accounting used by businesses depending on their peculiar needs. Below are the type of accounting methods:
- Cash basis is when revenues and expenses are recognised when cash is recieved or paid out.
-Accrual basis is when revenue and expenses are recognised when they are earned. For example if services are rendered to a client that will pay in a week's time, since service has already been given it is considered that the future payment has been earned.
- Modified basis combines elements of cash and accrual basis. For example considering short term assets like accounts receivable and accounts payable as cash items. Long term assets are recorded on accrual basis.
- Hybrid basis is used when cash and accrual methods are used for various expenses and tax. Mostly it is used for internal accounting purposes.
In this scenario Hariette would like to review the income and expenses that were actually paid last month. This requires a cash basis that shows actual amount recieved and paid last month. Account receivable and payable are not considered.
In setting aside money for tax she will employ accrual basis accounting. It is an expense that is estimated for future use.
So the hybrid basis is the method that will be most suitable.
Answer:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
Step-by-step explanation:
Notation
represent the sample mean for the sample
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the mean and the sample deviation we can use the following formulas:
(2)
(3)
In order to calculate the critical value 
we need to find first the degrees of freedom, given by:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
Solution:
As we are given that f(1) = 0 .
It mean that 
is one of the factor of the given equation.
Remainder theorem can be applied as below:
Hence the factors are (x-1),(x+3) and (x+1).
Hence the correct option is B.
Answer:
80 cm³
Step-by-step explanation:
Density = mass/volume
1.19 = 95.2/volume
Volume = 95.2/1.19
= 80
