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2 years ago

Which is the domain of the function f(x) = Negative five-sixths (three-fifths) Superscript x?

Mathematics

1 answer:

amm18122 years ago

8 0

Answer:

All real numbers less than 0

Step-by-step explanation:

I think it's this one because greater than 0 is wrong

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[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

2 years ago

After being dropped from a platform, a ball bounces several times. The graph shows the height of the ball after each bounce.

Paul [167]

Answer-

End behavior for increasing x represents that the height of each bounce will approach 0.

Solution-

From the graph the exponential equation is,

$y=100e^{(-0.35x)}$

From the properties of negative exponential function properties, as x increases, the value of y decreases.

So, in this case, as x or number of bounce increases, y or the height of bounce decreases. And eventually the value becomes zero.

Therefore, end behavior for increasing x represents that the height of each bounce will approach 0.

5 0

2 years ago

The formula for percentage increase I (given as a decimal) of an investment is I=S−PP, where P is the purchase price and S is th

sattari [20]

18.75/75=(75/75) -
p =(75-18.5)/75
p=56.5/75
p=0.75(3recurring)

5 0

2 years ago

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A rectangular pool is 20 feet wide and 50 feet long. A deck used for sunning surrounds the pool. The deck is the same width all

fredd [130]

The answer is B. 3 feet

3 0

2 years ago

Find the missing term. () + (7 − 3i) + (5 + 9i) + 13i = 10 − 5i.

kotegsom [21]

X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

Subtract 13i from both sides

x + (7 -3i) + (5 + 9i) = 10 - 18i

Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.

x + (7 - 3i) = 5 - 27i

Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.

x = -2 - 24i

5 0

2 years ago

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