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kodGreya [7K]
1 year ago
6

At Brighton Middle School, Mr. Yule asked 50 randomly selected students from each grade level about their favorite subject, and

12 chose science. He used this data to draw the inference that about 25% of middle school students will indicate science is their favorite subject. If there are 200 students altogether, did he make a reasonable inference?
Mathematics
2 answers:
Ugo [173]1 year ago
7 0

Answer:

Yes, he made a reasonable inference by saying about 25 percent of students choose the science.

Step-by-step explanation:

Given that

Number of students for survey = 50

Number of students who choose science = 12

Now

Percentage of student who choose science = \frac{12}{50} x 100

Percentage of student who choose science = \frac{12*100}{50}

Percentage of student who choose science = 24 %

Now as Mr. Yule said "about 25" percent of students choose the science it can be treated as reasonable approximation.

Now if the number of students in survey become 200, then we can expect 12 out of every 50 students would choose the science. So, in total 48 students would choose the science.

Now lets calculate the percentage of students who choose science.

Percentage of student who choose science = \frac{48}{200} x 100

Percentage of student who choose science = \frac{48*100}{200}

Percentage of student who choose science = 24 %



umka2103 [35]1 year ago
3 0

Answer:

D

"Yes, mr yule's sample is random and representative of the population."

^is the answer. :)

Step-by-step explanation:

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The price of a pair of shoes is $63.20. The sales tax rate is 4.5 percent. How much sales tax would you pay if you bought these
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What’s the 38th term of the arithmetic sequence 31,40,49,58?
Trava [24]

Answer:

a_3_8=364

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference

we have

31,40,49,58,...

Let

a_1=31\\a_2=40\\a_3=49\\a_4=58

we have that

a_2-a_1=40-31=9

a_3-a_2=49-40=9

a_4-a_3=58-49=9

so

The common difference is equal to 9

We can write an Arithmetic Sequence as a rule:

a_n=a_1+d(n-1)

where

a_n is the nth term                                                              

a_1 is the first term

d is the common difference                        

n is the number of terms

Find the 38th term of the arithmetic sequence

we have                  

a_1=31\\d=9\\n=38              

substitute the values

a_3_8=31+9(38-1)

a_3_8=31+9(37)

a_3_8=364

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A power failure on the bridge of a Great Lakes freighter has resulted in the ship's navigator having to do her own calculations.
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Answer:

1) The ship is closer

2) 675.73 m

Step-by-step explanation:

1) The given parameters are;

The initial angle between the ship's course and the lighthouse = 32°

The final angle between the ship's course and the lighthouse = 72°

The distance traveled by the sip between he two positions = 1500 m

Therefore we have a triangle formed between the distance covered by the ship and the two distances of the ship from the lighthouse, a and b

Where;

a = The initial distance fro the lighthouse

b = The final distance fro the lighthouse

The angles of the triangle are

32°, (180 - 72) = 108° and 180 - 32 - 108 = 40°

By sine rule we have;

1500/(sin(40)) = a/(sin(108)) = b/(sin(32)) =

Therefore, a = sin(108°) × 1500/(sin(40°)) = 2219.37 m

b = (sin(32°)) × 1500/(sin(40°)) = 1236.61 m

Therefore, a  > b

The initial distance fro the lighthouse > The final distance fro the lighthouse, which shows that the ship is closer

2) By cosine rule we have

a² = b² + c² - 2× b×c×cos(A)

Where the given measurements by Kendra are;

410 m and 805 m with an included (in between) angle of 57°, we have;

Let b = 410 m, c = 805 m, and A  = 57°, we have;

a² = 410^2 + 805^2 - 2× 410×805×cos(57 degrees) = 456608.77 m²

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jarptica [38.1K]

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Step-by-step explanation:

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If you decide to take your two furry friends to be groomed,

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the total discounted price for two dogs to be groomed would be

13 + 9.75 = 22.75

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