Sam painted 3 pictures.ellie painted twice as many pictures as Sam how many pictures did they paint altogether
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<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>
This is called the pythagorean theorem: a^2 + b^2 = c^2.
Basically, the sum of one side squared + the side of another side squared = the length of the longest side (or hypotenuse).
We have to do the following math:
4 * 4 = 16
6 * 6 = 36
16 + 36 = 52.
We know that 52 = c^2
So we have to
to get 7.21
You do not agree with Ted.
Basically, the sum of one side squared + the side of another side squared = the length of the longest side (or hypotenuse).
We have to do the following math:
4 * 4 = 16
6 * 6 = 36
16 + 36 = 52.
We know that 52 = c^2
So we have to
You do not agree with Ted.