The vector product of 
and the magnitude of 
is 
Further explanation:
Given:
Vector a is 
Vector b is 
Explanation:
The cross product of a \times b can be obtained as follows,
The vector can be expressed as follows,
The magnitude of can be obtained as follows,
43404
The vector product of and the magnitude of is
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Vectors
Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.
The answer to the question is B.
Answer:
Step-by-step explanation:
The answer is 3 /8/33.
step by step explanation
First, we can write:
x
=
3
.
¯¯¯¯
24
Next, we can multiply each side by
100
giving:
100
x
=
324
.
¯¯¯¯
24
Then we can subtract each side of the first equation from each side of the second equation giving:
100
x
−
x
=
324
.
¯¯¯¯
24
−
3
.
¯¯¯¯
24
We can now solve for
x
as follows:
100
x
−
1
x
=
(
324
+
0
.
¯¯¯¯
24
)
−
(
3
+
0
.
¯¯¯¯
24
)
(
100
−
1
)
x
=
324
+
0
.
¯¯¯¯
24
−
3
−
0
.
¯¯¯¯
24
99
x
=
(
324
−
3
)
+
(
0
.
¯¯¯¯
24
−
0
.
¯¯¯¯
24
)
99
x
=
321
+
0
99
x
=
321
99
x
99
=
321
99
99
x
99
=
3
×
107
3
×
33
x
=
3
×
107
3
×
33
x
=
107
33
Now, we can convert this improper fraction to a mixed number:
x
=
107
33
=
99
+
8
33
=
99
33
+
8
33
=
3
+
8
33
=
3
8
33
3
.
¯¯¯¯
24
=
3
8
33
In this item, it is assumed that we are to determine the speed at which the car will have the best gas mileage. This can be done by deriving the equation and equating it to zero.
M(s) = -1/28s² + 3s - 31
Deriving,
dM(s) = (-1/28)(2s) + 3 = 0
s = 42
Hence, the speed at which the best mileage is achieved is mi/h.
