Misha wants to spend some time playing guitar in uses the computer before dinner dinner will be ready in 45 minutes or less he w
ants to spend at least 15 minutes playing guitar which graph represents the amount of time Misha can spend playing guitar and use the computer
2 answers:
Answer:
<h2>Graph B.</h2>Step-by-step explanation:
Choices are attached.
According to the problem, the total time restriction is 45 minutes, because dinner will be ready in 45 minutes or less, this means that the area of solution must be under 45.
Addiotionally, he want to play guitar for at least 15 minutes, this means that the area of solution values more than x = 15.
If we apply these restriction, we would find the the solution is graph B, because the shaded area is under the 45-line and after the vertical line which expresses guitar time.
Therefore, the right answer is B.
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Answer:
its 13
Step-by-step explanation:
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Answer:
1) 22.66%
2) 20
Step-by-step explanation:
The scores of a test are normally distributed.
Mean of the test scores = u = 22
Standard Deviation = = 4
Part 1) Proportion of students who scored atleast 25 points
Since, the test scores are normally distributed we can use z scores to find this proportion.
We need to find proportion of students with atleast 25 scores. In other words we can write, we have to find:
P(X ≥ 25)
We can convert this value to z score and use z table to find the required proportion.
The formula to calculate the z score is:
Using the values, we get:
So,
P(X ≥ 25) is equivalent to P(z ≥ 0.75)
Using the z table we can find the probability of z score being greater than or equal to 0.75, which comes out to be 0.2266
Since,
P(X ≥ 25) = P(z ≥ 0.75), we can conclude:
The proportion of students with atleast 25 points on the test is 0.2266 or 22.66%
Part 2) 31st percentile of the test scores
31st percentile means 31%(0.31) of the students have scores less than this value.
This question can also be done using z score. We can find the z score representing the 31st percentile for a normal distribution and then convert that z score to equivalent test score.
Using the z table, the z score for 31st percentile comes out to be:
z = -0.496
Now, we have the z scores, we can use this in the formula to calculate the value of x, the equivalent points on the test scores.
Using the values, we get:
Thus, a test score of 20 represent the 31st percentile of the distribution.