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Cerrena [4.2K]
1 year ago
13

Peter has 96 stamps and Sam has 63. How many stamps should Sam give Peter so that Peter will have twice as many stamps as Sam?

Mathematics
2 answers:
MAXImum [283]1 year ago
4 0
96÷2=48
63-48=15

So Sam should give Peter 15 of his stamps so that Peter will have twice as many stamps as him.
Alona [7]1 year ago
4 0

Answer:

  • Sam must give Peter <u>10 stamps</u> so that Peter has twice as much as him.

Step-by-step explanation:

Although the exercise could be done using equations, I will teach you a much simpler method to find the answer to this type of exercise: add the stamps of Sam and Peter:

  • 96 + 63 = 159

Since one must have twice the other, you will have to divide the total value into 3 (then two parts will correspond to Peter and 1 one to Sam)

  •  159/3 = 53

With this value, <u>Sam must have only 53 stamps and give the rest to Peter, and since Sam has 63 stamps, he will have to give Peter 10, with which Peter will have 106 stamps, which is double 53</u>.

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The length of time Y necessary to complete a key operation in the construction of houses has an exponential distribution with me
Angelina_Jolie [31]

Answer:

Reference The length of time Y necessary to. ... construction of houses has an exponential distribution with mean 10 hours. The formula C = 100 + 40Y + 3Y 2 relates the cost C of completing this operation to ... Find the mean and variance of C. ... The length of time necessary to complete a key operation in the construction of ...

Step-by-step explanation:

5 0
2 years ago
Clint is in study hall reading the hunger games after 20 minutes he is on page 151 after 45 minutes he's on page 181 how many pa
Mademuasel [1]

After 20 minutes Clint is on page = 151

After 45 minutes Clint is on page = 181

Time slot = 45-20=25 minutes

Difference in pages in 25 minutes = 181-151=30 pages.

Lets suppose Clint is reading each page at same pace.

So , In 25 minutes, he can read = 30 pages

In 1 minute he can read = \frac{30}{25}=1.2 pages

Initial time is 20 minutes, so he can read the number of pages in 20 minutes = 20\times1.2=24

So, number of pages Clint read prior to study hall were =

151-24=127 pages.

6 0
2 years ago
There are 200 students in the 7th grade class at Brookside Middle School. Of these students, 12% play volleyball and 15% play ba
Phoenix [80]
P(volleyball and baseball) = 4/200 x 100 = 2%
P(either volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.

25% play either volleyball or baseball.
4 0
2 years ago
Read 2 more answers
In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa
MakcuM [25]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

Step-by-step explanation:

Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

X_{2}=9 represent the number of renters who would buy the security system

n_{1}=140 sample 1

n_{2}=60 sample 2

p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

p_{2}=\frac{9}{60}= 0.15 represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

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Rita does chores for her neighbors and makes $45 each weekend. She owes her sister $80. Rita has $178 in coins and a collection
mina [271]
The money she owes her sister $80
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