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sveticcg [70]
2 years ago
13

Un teren de 220 ha trebuie arat in 3 zile.Stiind ca a doua zi s-a arat de 1,5 ori mai mult ca in frima zi,iar in a treia zi s-a

arat de 2 ori mai mult ca in a doua zi,aflati cate hectare s-au arat in fiecare zi.
Mathematics
1 answer:
AVprozaik [17]2 years ago
5 0
I need a translation
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Marge cut 16 pieces of tape for mounting pictures on posterboard each piece of tape is 3/8 inches long how much tape did Marge u
daser333 [38]

Answer:

6 inches of tape

Step-by-step explanation:

To find the total amount of tape that Marge used, you can take the measure of each piece (\frac{3}{8}) and multiply by the total number of pieces cut (16):

\frac{3}{8}*\frac{16}{1}=\frac{48}{8}=6inches

So, Marge used 6 inches of tape altogether.

7 0
2 years ago
A rectangle is 5 √7 + 2 √3 meters long and 6 √7 - 3 √3 meters wide. a. Find the perimeter of the rectangle in simplest form. 2 b
Lunna [17]
I think the answer is 16.70
6 0
2 years ago
A ferry traveled \dfrac16 6 1 ​ start fraction, 1, divided by, 6, end fraction of the distance between two ports in \dfrac37 7 3
Ugo [173]

Answer:

<em>The ferry can travel \frac{7}{18} of the distance between the two ports in one hour.</em>

Step-by-step explanation:

A ferry traveled \frac{1}{6} of the distance between two ports in \frac{3}{7} hour.

Suppose, the ferry traveled x of the distance between the two ports in one hour.

So, the <u>equation according to the ratio of "distance" to "time"</u> will be.......

\frac{\frac{1}{6}}{\frac{3}{7}} =\frac{x}{1} \\ \\ x=\frac{1}{6}\times \frac{7}{3}= \frac{7}{18}

Thus, the ferry can travel \frac{7}{18} of the distance between the two ports in one hour.

5 0
2 years ago
Read 2 more answers
An electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are l
Tju [1.3M]

Answer:

Step-by-step explanation:

given that an  electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each

Sample space for selecting one resistor from first box

= {9, 10, 11, 12, 13}

A = {11,12,13} (because >10)

Sample space for selecting one resistor from second  box

={18,19,20,21,22}

B={18}

Sample space for sum would be

{27, 28, 29, 30, 31, 32, 33, 34, 35}

C = {(9,19) , (10,18)}

8 0
2 years ago
Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

p_v =2*P(z>0.546)=0.585  

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

4 0
2 years ago
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