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Free_Kalibri [48]
1 year ago
10

At the bank, Brent exchanges $50 in bills for 50 one-dollar coins. The total mass of the coins is 405 grams. ESTIMATE the mass o

f 1 one-dollar coin
Mathematics
2 answers:
Ksivusya [100]1 year ago
5 0

Hello!

At the bank, Brent exchanges $50 in bills for 50 one-dollar coins. The total mass of the coins is 405 grams. ESTIMATE the mass of 1 one-dollar coin

Data:  

$50 dollars in bills → 50 coins of one dollar  

Estimate the mass of one dollar coin

Solving:  

50 coins → 405 grams

1 coin → y

\dfrac{50}{1} = \dfrac{405}{y}

The rule of three

50*y = 405*1

50\:y = 405

y = \dfrac{405}{50}

\boxed{\boxed{y = 8.1}}\end{array}}

Answer:

\boxed{\boxed{\boxed{x \approx 8\:grams/coin}}}\qquad\checkmark

_____________________________

I Hope this helps, greetings ... Dexteright02! =)

Anarel [89]1 year ago
4 0
To find the answer, you should divide 405 by 50 to find the mass of one coin. The formula should look like this:
\frac{405}{50}
= 8.1
The exact mass is 8.1 grams, but because you want an estimate, the answer should be
About 8 grams for the mass of 1 one-dollar coin
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Hello!

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The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

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Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

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I hope it helps!

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