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2 years ago

10

A 5 hour conference booking is required for an office party for 120 people which includes a buffet dinner. Hotel 5 has recently

increased the total charges by 10 . How much would this booking now cost from hotel 5?

1 answer:

SpyIntel [72]2 years ago

5 0

Answer: I think that the cost now from hotel 5 would be $15.00.

Step-by-step explanation:

5 hours = $5.00

10 hours = $10.00

15 hours = $15.00

20 hours = $20.00

25 hours = $25.00

You might be interested in

Mike is 5 years old and Randy is 8 years old. Select all proportional relationships that have the same ratio to that of Mike and

Yanka [14]

Answer:

The ratio is multiplying 1.6 so just pick all the proportional relationships where you have to multiply by 1.6.

Step-by-step explanation:

Proportional relationships man you have to multiply, but since I didn't know what you multiplied 5 to get to 8 I divided.

8÷5=1.6

And if you want to check your answer then multiply.

5×1.6=8

<u><em>Could I please have BRAINLIEST?</em></u>

5 0

2 years ago

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig

Keith_Richards [23]

Answer:

1. Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

We need to find the mean for each group first and the grand mean.

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

If we apply the before formula we can find the mean for each group

$\bar X_A = 27$ , $\bar X_B = 24$ , $\bar X_C = 30$ . And the grand mean $\bar X = 27$

Now we can find the sum of squares between:

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

Each group have a sample size of 4 so then $n_j =4$

$SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72$

The degrees of freedom for the variation Between is given by $df_{between}=k-1=3-1=2$ , Where k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

$MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36$

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

$SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306$

And the degrees of freedom are given by:

$df_{within}=N-k =3*4 -3 = 12-3=9$ . N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

$MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34$

C. 34

Part 4

The test statistic F is given by this formula:

$F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059$

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is $F_{crit}=8.02$

B. 8.02

5 0

1 year ago

X=a-2by(2) make y the subject

sladkih [1.3K]

Answer:

y = √{(a - x)/2b}

Step-by-step explanation:

x=a-2by²

2by² = a - x

divide through by 2b

y² = (a - x)/2b

y = √{(a - x)/2b}

3 0

2 years ago

The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,

juin [17]

Answer:

The width is: $w(x)=4x^2$

The length is $l(x)=2x^2+3x+5$

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

$a(x)=8x^5+12x^3+20x^2$

The width of the rectangle is the greatest common factor of $8x^5$ , $12x^3$ and $20x^2$

That is the width is: $w(x)=4x^2$

We now divide the area by the width to obtain the length of the rectangle:

$l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}$

This simplifies to:

$l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}$

$l(x)=2x^2+3x+5$

5 0

2 years ago

Read 2 more answers

Max finds the product 3/7 x 6. Which statement is true?

Mariulka [41]

The correct answer is choice B. When you are multiplying anything by a value greater than one, the answer you get will always be bigger than what you started with.

The reason lies with in the concept of multiplication.

If you have more than one group of something, you will have more than what you started with.

3 0

1 year ago