A 5 hour conference booking is required for an office party for 120 people which includes a buffet dinner. Hotel 5 has recently
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1.The isosceles triangle has sides of length 14, y, y
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.
Answer:
The approximate length of arc s is 14.1 inches
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
step 1
Find the circumference of the circle
The formula to calculate the circumference is equal to
we have
substitute
step 2
Find the approximate length of arc s
we know that
The circumference of a circle subtends a central angle of 360 degrees
so
using proportion
Find the arc length s for a central angle of 135 degrees
Answer:
There is no significant difference between the averages.
Step-by-step explanation:
Let's call
the mean of the “sentences” group
the standard deviation of the “sentences” group
the mean of the “intentional” group
the standard deviation of the “intentional” group
Then, we can calculate by using the computer
The <em>standard error of the difference (of the means)</em> for a sample of size 8 is calculated with the formula
So, the standard error of the difference is
<em>In order to see if there is a significant difference in the averages of the two groups, we compute the interval of confidence of 95% for the difference of the means corresponding to a level of significance of 0.05 (5%). </em>
<em>If this interval contains the zero, we can say there is no significant difference. </em>
<em>Since the sample size is small, we had better use the Student's t-distribution with 7 degrees of freedom (sample size-1), which is an approximation to the normal distribution N(0;1) for small samples. </em>
We get the which is a value of t such that the area under the Student's t distribution outside the interval
is less than 0.05.
That value can be obtained either by using a table or the computer and is found to be
Now we can compute our confidence interval
and the confidence interval is
[-6.057, 0.307]
Since the interval does contain the zero, we can say there is no significant difference in these samples.