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White raven [17]
2 years ago
6

How are conditional probability and independent events related?

Mathematics
1 answer:
artcher [175]2 years ago
8 0

Answer:

1. P(A|B) - option 2

2. does not affect - option 2

3. P(A) - option 1

Step-by-step explanation:

By the definition, the notation P(A|B) reads the probability of event A given that event B has occured. So, for the first gap correct choice is 2 - P(A|B).

If events A and B are independent, then the probability of event B occuring does not affect the probability of event A occuring. So, for the second gap correct choice is 2 - does not affect.

Events A and B are independent, then

P(A\cap B)=P(A)\cdot P(B)

Use formula for the conditional probability:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Since events A and B are independent, we get

P(A|B)=\dfrac{P(A)\cdot P(B)}{P(B)}=P(A)

So, for the third gap correct answer is 1 - P(A)

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The average lethal blood concentration of morphine is estimated to be 2.5 µg/mL with a standard deviation of 0.95 µg/mL. The dat
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Step-by-step explanation:

Let <em>X</em> = lethal blood concentration of morphine.

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*Use a <em>z</em>-table for the probability.

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If the area of the rectangle is 120, what is the area of triangle cpd
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Answer:

Step-by-step explanation:

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Suppose that we want to investigate whether curfews correlate with differences in grades for students in middle school. We selec
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Answer:

Step-by-step explanation:

Hello!

Given the variables

X: Curfew of middle school students (Categorized Yes/No)

Y: Average grade of middle school students. (Categorized: A, B, C, and D)

The objective is to test if there is an association between both variables, you have to conduct a Chi-Square test of independence.

In the null hypothesis, you state that both variables are independent vs. the alternative hypothesis that the variables are dependent.

The hypotheses for this test are:

H₀: Pij= Pi. * P.j i= (1)Yes, (2)No; j= (1)A, (2)B, (3)C, (4)D

H₁: Te variables are not independent.

α: 0.05

X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~X_{(r-1)*(c-1)}

Where

Oij is the observed frequency for the i-row and j-column

Eij is the expected frequency for the i-row and j-column

r= number of categories in the rows

c= number of categories in the columns

X^2_{H_0}= 1.4796703

p-value: 0.687

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis. So using a 5% significance level, you can conclude that having a curfew and the average grades of middle schoolers are two independent variables.

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