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Amanda [17]
2 years ago
5

It takes 313131 employees and \$7500$7500dollar sign, 7500 to build a car, and it takes 191919 employees and \$4300$4300dollar s

ign, 4300 to build a motorcycle. Genghis Motors wants to spend more than \$84000$84000dollar sign, 84000 to build cars and motorbikes using at most 706706706 employees. Let CCC denote the number of cars they build and MMM the number of motorbikes they build. Write an inequality that represents the condition based on the number of employees. Write an inequality that represents the condition based on the number of dollars.
Mathematics
1 answer:
Liula [17]2 years ago
3 0

Answer:

a) 31c + 19m ≤ 706

b) 7500c + 4300m > 84000

Step-by-step explanation:

To build a car, we need 31 employees and $7500.

To build a motorcycle, we need 19 employees and $4300.

Let C denote the number of cars they build.

Let M denote the number of motorbikes they build.

Recall that ;

To build a career, we need 31 employees. To build "c" cars, we will need 31*c = 31c employees

To build a motorcycle, we need 19 employees. To build "m" motorcycle, we will need 19*m = 19m

Since the maximum number of employees used to build the car and motorcycle is at most 706, we have

31c + 19m ≤ 706

It takes $7500 to build car. To build "c" cars, we need 7500*c = $7500c

It also takes $4300 to build "m" motorcycles. We need 4300*m = $4300m

Since Genghis motors wont to spend more than $84000 on both cars and motorcycles, we have

7500c + 4300m > 84000

For the condition based on the number of employees, we have

31c + 19m ≤ 706

For the condition based on the number of dollars, we have

7500c + 4300m > 84000

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Step-by-step explanation:

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As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of <em>n</em> from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for <em>n</em> = 64 is:

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\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

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If the sample size is decreased then the standard deviation will increase.

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The standard deviation of the sample mean for <em>n</em> = 784 is:

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