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2 years ago

15

Beth sold half of her comic books and then bought nine more. She now had 28. With how many did sh begin?

2 answers:

rusak2 [61]2 years ago

5 0

Answer:

38

Step-by-step explanation:

hope this helps

Vladimir79 [104]2 years ago

3 0

Answer:

<h2><em><u>38</u></em></h2>

Step-by-step explanation:

She began with 38 books.

28 - 9 = 19

19(2) = 38

Hope this helps!

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1. Your furniture store sells two types of dining room tables. The first, type A, costs $265 and you make a $25 profit on each o

Gnom [1K]

Let x represent the number of type A table and y represent the number of type B tables.
Minimize: C = 265x + 100y
Subject to: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1

From, the graph the corner points are (20, 20), (39, 1), (30, 1)
For (20, 20): C = 265(20) + 100(20) = $7,300
For (39, 1): C = 265(39) + 100 = $10,435
For (30, 1): C = 265(30) + 100 = $8,050

Therefore, for minimum cost, 20 of type A and 20 of type B should be ordered.

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2 years ago

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Nikki dove into a pool and swam underwater the table shows how her depth changed during a 4 second time period which equation sh

Dvinal [7]

Answer:

I think the answer is d = 1.5t

Step-by-step explanation:

8 0

2 years ago

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

AleksAgata [21]

we are given

$12x^3-2x^2+18x-3$

Firstly, we will split terms

$2x^2*6x-1*2x^2+3*6x-1*3$

We can group first two and last two terms

$(2x^2*6x-1*2x^2)+(3*6x-1*3)$

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

$=2x^2(6x-1)+3(6x-1)$

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

$12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)$ ............Answer

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2 years ago

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A total of $150000 is invested in two funds paying 6.25% and 6% simple interest. If the total interest for the year is $9212.50,

Georgia [21]

Answer:

$85,000 at 6.25%
$65,000 at 6.00%

Step-by-step explanation:

Let x represent the amount invested at 6.25%. Then the total interest earned is ...

0.0625x + 0.0600(150,000 -x) = 9212.50

0.0025x = 212.50 . . . . . . subtract 9000, collect terms

x = 212.50/0.0025 = 85,000

150,000 - 85,000 = 65,000 . . . . amount invested at the lower rate

$85,000 is invested at 6.25%; $65,000 is invested at 6%.

3 0

2 years ago

Hank invested a total of $20,000, part at 7% and part at 10%. How much did he invest at each rate if the total interest earned i

jolli1 [7]

Answer:

The amount invested at 7% is $12,000 while the amount invested at 10% is $8,000

Step-by-step explanation:

The given parameters are;

The total amount Hank invested = $20,000

The interest earned in one year = $1640

Hank invested part of the $20,000 at 7% interest and part of the $20,000 at 10%

Let the part invested at 7% = X and the part invested at 10% = Y, we have;

7% of X + 10% of Y = $1640 which gives;

0.07×X + 0.1×Y = $1640.....................(1)

X + Y = $20,000.................................(2)

Multiply equation (1) by 10 and subtract equation (1) from equation (2) to get;

X + Y - 10×(0.07×X + 0.1×Y) = $20,000 - 10×$1640

X - 0.7·X - Y - Y = $20,000 - $16,400 = $3,600

0.3·X = $3,600

X = $3,600/0.3 = $12,000

X = $12,000

Y = $20,000 - X = $20,000 - $12,000 = $8,000

Y = $8,000

Therefore, the amount invested at 7% = $12,000 and the amount invested at 10% = $8,000.

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2 years ago

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