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Alexandra [31]
2 years ago
12

Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. Call t

he amount that Henri invested in stocks s and the amount he invested in bonds b.
Mathematics
2 answers:
Pie2 years ago
6 0

Answer:

Bonds: $4,500

Stocks: $19,500

Step-by-step explanation:

In order to solve this you just need to create a litte equation, to represent the bonds we will use "x" so Bonds equals "x" and the stocks are three times the amount of bonds plus 6,000 that is 3x+6,000, if you add both the result will be $24,000

So the equation would be:

x+ (3x+6,000)=24,000\\4x+6,000=24,000\\4x=24,000-6,000\\4x=18,000\\x=4,500

makvit [3.9K]2 years ago
4 0

Answer:

The solve of that problem is that Hernry invested $18.000 in stocks and $6.000 in bonds.

Step-by-step explanation:

First, to explain you have to do a multiplication about 6 on three. Like three times more than bonds, the result is 18. Then you have to do a  subtraction on $24.000 less $18.000, and the result is $6.000, so six is the amount on bonds. And is three times less than stocks, like the questions ask.

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Raymond bought 3/4 of a dozen rolls. How many rolls did he buy? Also, (another question) Jonathan rode 1.05 miles on Friday, 1.5
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Answer to question one:
9 rolls
Answer to question two:
2.8
5 0
1 year ago
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Michael pays $30 to enter a state fair, plus $4 for each ride. Which of the following equations represents his total cost? A. y=
omeli [17]
He spends 30 to enter and 4 per ride

y = 4x + 30....with x being the number of rides and y being the total cost
4 0
2 years ago
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A newspaper vendor sells three papers to 135 customers, the papers are the daily times, the observer and the new Nigeria. 70 cus
IRINA_888 [86]

Answer:

3 customers brought all the three papers.

Step-by-step explanation:

Let, D, O and N represents the three newspapers.

D = The daily times

O = The observer

N = The new Nigeria.

According to the given information,

n(D\cup O\cup N)=135, n(D)=70,n(O)=60,n(N)=50

n(D\cap O)=17, n(O\cap N)=15, n(D\cap N)=16

We know that,

n(A\cup B\cup C) = n(A) + n(B) + n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A) + n(A\cap B\cap C)

Using this formula, we get

n(D\cup O\cup N) = n(D)+n(O) + n(N)-n(D\cap O)-n(O\cap N)-n(N\cap D) + n(D\cap O\cap N)

135 =70+60+50-17-15-16 +n(D\cap O\cap N)

135 =132+n(D\cap O\cap N)

135 -132=n(D\cap O\cap N)

3=n(D\cap O\cap N)

Therefore, 3 customers brought all the three papers.

5 0
1 year ago
Emily is a songwriter who collects royalties on her songs whenever they are played in a commercial or a movie. Emily will earn $
Hitman42 [59]

Answer:

(6,2)

Step-by-step explanation:

Variable Definitions:

​x= the number of commercials

y= the number of movies

Each commercial earns Emily $50, so x commercials would earn her 50x dollars in royalties. Each movie earns Emily $150, so y movies would earn her 150y dollars in royalties. Therefore, the total royalties 50x+150y equals $600:

50x+150y=600

Since Emily's songs were played on 3 times as many commercials as movies, if we multiply 3 by the number of movies, we will get the number of commercials, meaning x equals 3y.

x=3y

Write System of Equations:

​50x+150y=600

x=3y

Solve for y in each equation:

1)  50x+150y=600

   150y=−50x+600

   y=-1/3x+4

2)  x=3y

    y=1/3x

The x variable represents the number of commercials and the yy variable represents the number of movies. Since the lines intersect at the point (6,2) we can say:

Emily's songs were played on 6 commercials and 2 movies.

​

 

4 0
1 year ago
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
Debora [2.8K]

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

6 0
1 year ago
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