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astra-53 [7]
2 years ago
12

Ribbon is only sold by the spool. A spool contains 25 yards of ribbon. Shannon needs 58 yards of ribbon to wrap all the presents

which is equivalent to 2.32 spools how many spools should she buy
Mathematics
2 answers:
ella [17]2 years ago
6 0

Answer:

\boxed{\text{3 spools}}

Step-by-step explanation:

\text{1 spool =25 yd}\\\text{Spools needed } = \text{58 yd} \times \dfrac{\text{1 spool}}{\text{25 yd}} = \text{2.32 spools}\\\\\text{However, Shannon can't buy part of a spool. She must $\textbf{round up}$ to the next integer.}\\\text{Shannon must buy $\boxed{\textbf{3 spools}}$ of ribbon}

lubasha [3.4K]2 years ago
3 0

Answer:

1 spool.

Step-by-step explanation:

It is given in the question that 58.0 yards of ribbon equivalent to 2.32 spool.

We have to find number of spools Shannon will buy which will be equivalent to 25 yard ribbon.

∵ 58 yards of ribbon = 2.32 spool

∴ 1 yard of ribbon = \frac{2.32}{58} spool

∴ 25 yards of ribbon = \frac{2.32}{58} × 25

                                  = 1 spool

Therefore, Shannon will buy 1 spool.

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Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc
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Answer:

a. p(x<= 5) = .15 + .4 + .25 = .8

C. .4(4.2) = 1.68

5.4(1-.4) = 3.24

3.24 + 1.68 = 4.92 ,, 4.92 > 4.55 so short is better

Step-by-step explanation:

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2 years ago
234,143 rounded to the nearest hundred
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234,100

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Step-by-step explanation:

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1 year ago
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A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400
KiRa [710]

Answer:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=400, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=400*0.2=80 \geq 10

n(1-p)=400*(1-0.2)=320 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=400*0.2=80

\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8

So then we can approximate the random variable as X \sim N(\mu = 80, \sigma = 8)

And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

8 0
2 years ago
The histogram shows the number of vacation days taken by employees in the past year. Based on the histogram, which statement is
Serhud [2]
The correct answer is b
8 0
1 year ago
A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one
WITCHER [35]
If a pair of fair dice is cast, the probability that the <span>sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:

\frac{P(sum\, of\, 9\, \cup\,3)}{P(3)}

The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.

</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.

Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
5 0
2 years ago
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