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kap26 [50]
1 year ago
10

Xavier is buying a new pair of snowshoes. They are regularly $85, but they are on sale for $68. What percent is the markdown?

Mathematics
1 answer:
Mandarinka [93]1 year ago
4 0

Answer:

25%

Step-by-step explanation:

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Adrian are 3 ani, iar tatăl lui are 34 de ani. Peste câți ani Adrian va fi de două ori mai tânăr decât tatăl său?
katrin [286]

Answer:

27 years

Step-by-step explanation:

Given that :

Adrian's age = 3

Father's age = 34

In how many years will Adrian be twice as young as his father?

Let the number of years = x

2(3 + x) = 34 + x

6 + 2x = 34 + x

2x - x = 34 - 6

x = 28

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1 year ago
Juan builds this pedestal for a trophy. What is the volume of the pedestal? Enter your answer in the box. in³ Three-dimensional
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The answer is is negative 0
4 0
1 year ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
1 year ago
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
1 year ago
Suppose the radius of a circle is \color{purple}{3}3start color purple, 3, end color purple. what is its circumference?either en
Vlada [557]

\text{Consider the circle of radius 3.}\\
\\
\text{we need to find the cirumference of the circle.}\\
\\
\text{we know that the circumference of the circle of radius r is given by}\\
\\
\text{circumference}=2\pi r\\
\\
\text{so using this formula, the circumference of the given circle is}

\text{Circumference}=2\pi r\\
\\
=2\pi \times 3\\
\\
=6\pi
\\
\text{so the circumference of the circle is}=6\pi\\
\\
\text{and in decimals, it gives}=6\times 3.14\\
\\
\Rightarrow \text{circumference}=18.84

Hence the circumference of the circle is: 6π  or  18.84 units

6 0
2 years ago
Read 2 more answers
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