What are the domain and range of f (x) = (one-fifth) Superscript x?
2 answers:
Answer:
The domain of the function is all real numbers and the range is all positive real numbers
Step-by-step explanation:
We have the following function and we want to find the domain and the range.
The function we have is an example of an exponential function with b > 0 and b ≠ 1. This types of functions in general have the following properties:
- It is always greater than 0, and never crosses the x-axis
- Its domain is the set of real numbers
- Its Range is the Positive Real Numbers
The domain of a function is the specific set of values that the independent variable in a function can take on.
When determining domain it is more convenient to determine where the function would not exist.
This function has no undefined points nor domain constraints. Therefore the domain is .
The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is .
We can check our results with the graph of the function.
You might be interested in
Answer:
Option A) outside
hope it helps..
have a great day!!!
Answer:
The quadratic equation form is x² - 9 x + 14 = 0
Step-by-step explanation:
Given in the question as ,
The solution of quadratic equation are x = 2 and x = 7
The constant K is a non-zero number
Now , let the quadratic equation be , ax² + bx + c = 0
And sum of roots =
product of roots =
So, 2 + 7 =
Or, 2 × 7 =
I.e = 9 ,
= 14
Or, b = - 9 a And c = 14 a
Put this value of b and c in standard form of quadratic equation
I.e ax² + bx + c = 0
Or, ax² - 9 ax + 14 a = 0
Or , a ( x² - 9 x + 14 ) = 0
∴ a = 0 And x² - 9 x + 14 = 0
Hence , The quadratic equation form is x² - 9 x + 14 = 0 Answer