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abruzzese [7]
2 years ago
13

What are the domain and range of f (x) = (one-fifth) Superscript x?

Mathematics
2 answers:
natka813 [3]2 years ago
7 0

Answer:

The domain of the function is all real numbers (-\infty,\infty) and the range is all positive real numbers (0,\infty)

Step-by-step explanation:

We have the following function f(x)=(\frac{1}{5} )^x and we want to find the domain and the range.

The function we have is an example of an exponential function f(x)=b^x with b > 0 and b ≠ 1. This types of functions in general have the following properties:

  • It is always greater than 0, and never crosses the x-axis
  • Its domain is the set of real numbers
  • Its Range is the Positive Real Numbers (0,\infty)

The domain of a function is the specific set of values that the independent variable in a function can take on.

When determining domain it is more convenient to determine where the function would not exist.

This function has no undefined points nor domain constraints. Therefore the domain is (-\infty,\infty).

The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is (0,\infty).

We can check our results with the graph of the function.

elena55 [62]2 years ago
5 0

Answer: answer is B

Step-by-step explanation:

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Step-by-step explanation:

given data

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front cost = 10 cents/in²

remainder sides cost = 2 cents/in²

to find out

the dimensions that will minimize the cost

solution

we consider here length = x and breadth = y and height = z

and

area of base = xy

area of front = xz

and area of remaining side = xz + 2yz     .....................1

so

cost of base will be = 5xy

cost of front = 10xz

cost of remaining side = 2 ( xz+ 2yz)        

and

total cost will be

total cost TC = 5xy + 10xz + 2 ( xz+ 2yz)  

total cost TC = 5xy + 10xz + 2xz+ 4yz

total cost TC = 5xy + 12xz + 4yz                  ....................2

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z = \frac{150}{xy}                  .......................3

now put z value in equation 2

total cost TC = 5xy + 12xz + 4yz    

total cost TC = 5xy + 12x\frac{150}{xy} + 4y\frac{150}{xy}

total cost TC = 5xy + \frac{1800}{y} + \frac{600}{x}     ...........4

now differentiate TC w.r.t x and y

TC (x) = 5y - \frac{600}{x^2}

TC (x) = 5x - \frac{1800}{y^2}

now equating with 0 these

5y - \frac{600}{x^2} = 0

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and

5x - \frac{1800}{y^2} = 0

x = \frac{360}{y^2}    

solve we get

y = 10.2598

x = 3.4199

now put x and y value in equation 3

z = \frac{150}{xy}  

z = \frac{150}{3.4199*10.2598}  

z = 4.2750

so minimum cost of construction box are x = x = 3.4199 in and y = 10.2598 in and z = 4.2750 in

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