The number of fish in Lake Karachay in Chernobyl, Ukraine were counted and recorded in the population chart below

Carolina is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus \$6$6dollar sign, 6 for each ho

Margarita [4]

For this case, the first thing we must do is define variables.

We have then:

t: number of hours

F (t): total charge

We write the function that models the problem:

$F (t) = 6t + b$

Where,

b: represents an initial fee.

We must find the value of b.

For this, we use the following data:

Her total fee for a 4-hour job, for instance, is $ 32.

We have then:

$32 = 6 (4) + b$

From here, we clear the value of b:

$32 = 24 + b$

$32-24 = b$

$b = 8$

Then, the function that models the problem is:

$F (t) = 6t + 8$

Answer:

the function's formula is:

$F (t) = 6t + 8$

7 0

2 years ago

If m<1 = (11x +2) and m<7 = (8x + 7) , find the value of 'x'

DanielleElmas [232]

Wait ill come right back at u let me solve

8 0

2 years ago

By coincidence, Kimberly’s Paint Supplies sold equal quantities of two paint colors yesterday: yellow and blue. All yellow paint

Damm [24]

Answer:

36 liters

Step-by-step explanation:

Yellow paint = 9 liters containers

Blue paint = 12 liters containers

Kimberly’s Paint Supplies sold equal quantities of two paint colors yesterday

What is the smallest amount of each paint color the store must have sold?

Find the Lowest common multiple of 9 liters and 12 liters

9 liters = 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

12 liters = 24, 36, 48, 60, 72, 84, 96, 108

The Lowest common multiple of 9 liters and 12 liters is 36 liters

Therefore, the smallest amount of each paint color the store must have sold to have equal quantities of two paint colors yesterday is 36 liters

7 0

2 years ago

Read 2 more answers

Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zarrin [17]

Correction:

Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0

2 years ago

A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-

sergiy2304 [10]

Answer:

The t-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

$CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}$

Here,

$\bar x_{d}$ = sample mean of the difference,

$s_{d}$ = sample standard deviation of the difference,

n = sample size (both samples are of same size).

$t_{\alpha/2, (n-1)}$ = critical value of t

(n - 1) = degrees of freedom

The information provided is:

n = 5

Confidence level = 95%

The critical value of t is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}$

$=t_{0.025, 4}$

$=2.776$

*Use a t-table for the critical value of t.

Thus, the t-value used for the 95% confidence interval of paired data is 2.776.

4 0

2 years ago