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Setler79 [48]
2 years ago
7

The area of a trapezoid is 140 cm2 and the height is 20 cm. What is the sum of the bases?

Mathematics
2 answers:
vfiekz [6]2 years ago
8 0

Answer:

D. 7 cm

Step-by-step explanation:

Reil [10]2 years ago
6 0
D 7
A million apologies if I’m wrong half of my brain is still on vacation!
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Answer:

she can buy 3 T-shirts

Step-by-step explanation:

200.00-87.96=112.04

112.04-30-30-30=22.04

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2 years ago
2. The ground below your feet moves at the rate at which
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I’m just going off of what I was told in fifth grade, and we were told it was finger nails. Hope this helps!
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2 years ago
What is the value of x in the figure below? In this diagram, ABD~CAD
olga55 [171]

Answer:

x = 25/4

Step-by-step explanation:

Because of the known similarity of the triangles, we know that

10       x

----- = ----

16      10

Cross-multiplying, we get 16x = 100, and thus x = 100/16 = 50/8 = 25/4

x = 25/4

4 0
2 years ago
Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
Pachacha [2.7K]

Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem

Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?

For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{1.1}

Z = 1.64

Z = 1.64 has a pvalue of 0.9495.

This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.

For the average of the sample

What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?

Now, we need to find the standard deviation of the sample before using the zscore formula. That is:

s = \frac{\sigma}{\sqrt{110}} = 0.1.

Now

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{0.1}

Z = 18

Z = 18 has a pvalue of 0.9999.

This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

7 0
2 years ago
Suppose you adding 43 and 28 will you regroup ? Explain
Kryger [21]
Yes you will regroup because 8+3 equals 11 so you would bring the 1 down and add the other to the 4 and 2
3 0
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