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viktelen [127]
2 years ago
7

A solid wooden block in the shape of a rectangular prism has a length,width and height of 3/8 cm, 1/8 cm, and 5/8 cm, respective

ly.
The volume of the block is ____ cubic cm. The number of cubic wooden blocks with a side length of 1/8 cm that can be cut from the rectangular block is ____.
Mathematics
2 answers:
RUDIKE [14]2 years ago
5 0

Answer: The volume of the block is \frac{15}{512}\ cm^3 cubic cm. The number of cubic wooden blocks with a side length of 1/8 cm that can be cut from the rectangular block is 15.

<u>Step-by-step explanation</u>:

The volume of a rectangular prism is given by :-

V=lwh

Given: A solid wooden block in the shape of a rectangular prism has a length,width and height of 3/8 cm, 1/8 cm, and 5/8 cm, respectively.

Now, the volume of a wooden block will be :-

V=\frac{3}{8}\times\frac{1}{8}\times\frac{5}{8}=\frac{15}{512}\ cm^3

The volume of cubic block with side length of 1/8 cm is given by :-

V=(side)^3=(1/8)^3=\frac{1}{512}\ cm^3

Now, the number of cubic wooden blocks with a side length of 1/8 cm that can be cut from the rectangular block  is given by :-

\frac{\text{Volume of wooden block}}{\text{Volume of cubic block}}=\frac{\frac{15}{512}}{\frac{1}{512}}=15

levacccp [35]2 years ago
3 0
Volume of a rectangular prism: length times width times height:
3/8 * 1/8 *5/8= 15/512 cubic cm

the volume of a small cubic wooden block: 1/8 *1/8 *1/8=1/512

How many small cubic blocks: the volume of the solid wooden block divided by the volume of the small cubic block:
15/512 ÷ 1/512 =15
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a. 205320

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c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

Step-by-step explanation:

a) The number of ways to dustribute exams among the TA's is:

n / (n - r)!

n= number of things to choose from

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60P3= 60! / (60 - 3)!

(60)(59)(58)(57)! / (57)!

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B) The number of ways to dustribute the exams among the TA's is:

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C) The required number of ways is:

60C25 + 60C20 + 60C15

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2 years ago
Suppose has a solution. Explain why the solution is unique precisely when has only the trivial solution. Choose the correct answ
Margarita [4]

Complete question is;

Suppose Ax = b has a solution. Explain why the solution is unique precisely when Ax = 0 has only the trivial solution. Choose the correct answer.

A. Since Ax = b is inconsistent, its solution set is obtained by translating the solution set of Ax = 0. For Ax = b to be inconsistent, Ax = 0 has only the trivial solution.

B. Since Ax = b is consistent, its solution set is obtained by translating the solution set of Ax = 0. So the solution set of Ax = b is a single vector if and only if the solution set of Ax = 0 is a single vector, and that happens if and only if Ax = 0 has only the trivial solution.

C. Since Ax = b is inconsistent, then the solution set of Ax = 0 is also inconsistent. The solution set of Ax = 0 is inconsistent if and only if Ax = 0 has only the trivial solution.

D. Since Ax = b is consistent, then the solution is unique if and only if there is at least one free variable in the corresponding system of equations. This happens if and only if the equation Ax = 0 has only the trivial solution.

Answer:

Option B: Since Ax = b is consistent, its solution set is obtained by translating the solution set of Ax = 0. So the solution set of Ax = b is a single vector if and only if the solution set of Ax = 0 is a single vector, and that happens if and only if Ax = 0 has only the trivial solution

Step-by-step explanation:

There are different ways of explaining this but we will explain it algebraic ally.

If Ax = b has a solution, then it can be said to be unique if and only if every column of A will be a pivot column. Now, If every column of A will be a pivot column, then it means that there are no free variables, and thus the homogeneous equation will have only the trivial solution.

Also homogeneous equations are always constant.

Thus the correct option is Option B: Since Ax = b is consistent, its solution set is obtained by translating the solution set of Ax = 0. So the solution set of Ax = b is a single vector if and only if the solution set of Ax = 0 is a single vector, and that happens if and only if Ax = 0 has only the trivial solution

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