A. imagine that you are one of the people who left the luncheon with a contagious disease and interacted with an average of 9 di
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Answer:
(a) The probability of exactly three flaws in 150 m of cable is 0.21246
(b) The probability of at least two flaws in 100m of cable is 0.69155
(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063
Step-by-step explanation:
A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by
for x = 0, 1, 2, ...
where , the mean number of successes.
(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is
The probability of exactly three flaws in 150 m of cable is
(b) The probability of at least two flaws in 100m of cable is,
we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is
(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is
The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is
Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
Answer:
The expression that can be used to determine the final cost of the game is
1.06(0.88 y) ⇒ (C)
Step-by-step explanation:
- If the price of an item is discounted, that mean its new price will be less its initial price
- The taxes on item, makes its new price greater than the initial price because tax is add
Let us solve the problem
∵ Ella purchased a game that was on sale for 12% off
→ That means the new price will (100% - 12%) of the initial price
∵ y represented the initial price of the game
→ Multiply y by (100% - 12%) to get the new price
∴ The new price = y (100% - 12%)
∴ The new price = y (88%)
→ Change 88% to normal number by divide it by 100
∴ The new price = y ()
∴ The new price = 0.88 y
∵ The sales tax in her county is 6%
→ That means the final cost will be (100% + 6%) of 0.88 y
∴ The final cost = (100% + 6%) × (0.88 y)
∴ The final cost = 106% × (0.88 y)
→ Change 106% to normal number by divide it by 100
∴ The final cost = × (0.88 y)
∴ The final cost = 1.06(0.88 y)
The expression that can be used to determine the final cost of the game is 1.06(0.88 y)