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Studentka2010 [4]
2 years ago
14

A machine used to fill cereal boxes dispenses, on the average, μ ounces per box. The manufacturer wants the actual ounces dispen

sed Y to be within 1.1 ounce of μ at least 75% of the time. What is the largest value of σ, the standard deviation of Y, that can be tolerated if the manufacturer's objectives are to be met?
Mathematics
1 answer:
irga5000 [103]2 years ago
4 0

Answer: 1/2

Step-by-step explanation:

First step: we will use Tchebyscheff's theorem. The theorem can help us to explain random variables with finite variance as well as mean.

P (|Y-u| < or equals to 1) | > or equals to 0.75

= 1 - 1/2

Therefore, w= 2

Step 2: we use Tchebyscheff's inequality, which is:

= -2¶ + u < y < 2¶ + u

Therefore, we have; --2¶ + u

= 1 + u

1= K¶

¶ = 1/2.

Please take note that ¶ is represented as sigma symbol.

Since I can't get the symbol here with me. Also the u repres represent 'micro' symbol

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The mean number of students in a classroom at school a is 32.5 and there are 25 classrooms. The mean number of students at schoo
Airida [17]

We have given three school there, School A, School B and School C.

We are going to use following formula.

Total number of student in a school = Mean of number of student × Number of classrooms.

School A

Mean of students in School A = 32.5.

Number of classroom in School A = 25.

Number of students in School A = Mean × number of classrooms = 32.5×25 = 812.5


School B

Mean of students in School B = 29.6.

Number of classroom in School B = 12.

Number of students in School B = Mean × number of classrooms = 29.6×12 = 355.2


School C

Mean of students in School C = 15.3.

Number of classroom in School C = 10.

Number of students in School C = Mean × number of classrooms = 15.3×10 = 153.


Total sum of number of classes in all schools = 25+12+10 = 47.

Total sum of all students in all schools = 812.5 +355.2 +153 = 1320.7 .

The mean number of students per classroom for all the schools combined =

\frac{Total \ sum \ of \ all \ students \ in \ all \ schools}{Total \ sum \ of \ number \ of \ classes \ in \ all \ schools}

= \frac{1320.7}{47} = 28.1

The mean number of students per classroom for all the schools combined= 28.1

4 0
2 years ago
The square shown has a perimeter of 32 units. The square is rotated about line k.
Bad White [126]

A cylinder with a circumference of about 50 units is formed.

Step-by-step explanation:

Step 1:

The perimeter of the square is 32 units. The perimeter of a square is given by 4 times its side length.

(4) sidelength = 32, sidelength = \frac{32}{4} = 8.

So the side length of the square is 8 units.

If a square is rotated a cylinder will be formed. So the options with a cone are wrong as a cone is formed when a triangle is rotated.

Step 2:

To calculate the circumference of the cylinder, we multiply 2π with the radius. The radius is the same as the side length of the square. So r is 8 units.

The circumference of the cylinder = 2\pi r = (2) (3.1415)(8) = 50.264.

So the circumference of the cylinder is approximately equal to 50 units so the answer is the fourth option, a cylinder with a circumference of about 50 units.

4 0
2 years ago
Read 2 more answers
1/2(6+3p)-3/4(8-10p)<br>Expand and simplify <br>show all steps
olganol [36]
\frac{6+3p}{2} -  \frac{3}{4} (8 - 10p) \\ \\  \frac{6 + 3p}{2} -  \frac{3(8-10p)}{4} \\ \\   \frac{6+3p}{2} -  \frac{3 \times 2(4 - 5p)}{4} \\ \\  \frac{6+3p}{2} -  \frac{6(4-5p)}{4} \\ \\  \frac{6+3p}{2} -  \frac{3(4-5p)}{2}  \\ \\  \frac{6+3p - 3(4-5p)}{2} \\ \\   \frac{3(2 +p - 4 + 5p}{2} \\ \\  \frac{3(2 + (p + 5p) - 4)}{2} \\ \\  \frac{3(2+6p-4)}{2} \\ \\  \frac{3 \times 2 (1 + 3p-2)}{2} \\ \\  \frac{3 \times 2(3p - 1)}{2} \\ \\  \frac{6(3p -1 }{2} \\ \\ 3(3p - 1) \\ \\ Answer: \fbox {3(3p-1)}
7 0
2 years ago
Solve the linear equation for x <br><br> -4.8(6.3x-4.18) =-58.56<br><br> X=
lyudmila [28]

Answer:

x= 2.6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0
2 years ago
Q. You are working on an air conditioning system. A roll of cylindrical copper tubing has an outside diameter of 7/8 inch and an
diamong [38]

The refrigerant can hold 1.92 ft³

Step-by-step explanation:

The formula to apply is that of volume

v=π *r²*h where v is volume, r is radius of cylindrical object and h is height   of tubing

Finding volume of using outside  diameter

v=π*7/16*7/16*12

v=49/64 *3/1 *3.14

v=7.22 ft³

Volume using inside diameter

v=π*r²*h

v=3.14*3/8*3/8*12

v=5.30 ft³

Volume the refrigerant  can hold is;

7.22-5.30 = 1.92 ft³

Learn More

Volume of a cylindrical object:brainly.com/question/2665971

Keywords :conditioning,system,roll,copper tubing,refrigerant

#LearnwithBrainly

5 0
2 years ago
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