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julia-pushkina [17]
2 years ago
14

Martha is planting a garden that will cover up to 400 square feet. She wants to plant two types of flowers, daises and roses. Ea

ch daisy covers 2 square feet and each rose covers 1.5 square feet. Daises cost $2 a piece and each rose costs $3 a piece. Martha doesn't want to spend over $500 on her garden
Mathematics
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

150 daisies and 66 roses.

Step-by-step explanation:

To carry out the exercise, you have to propose equations with the requirements of Martha, a garden of 400 square feet and not spend more than $ 500. Let X be the number of daisies and Y the number of roses. We have left that:

2 * X + 1.5 * Y = 400 (1)

2 * X + 3 * Y = 500 (2)

We have two equations with two unknowns, therefore we proceed to solve. If we subtract (1) in (2) we have:

2 * X + 3 * Y - 2 * X - 1.5 * Y = 500 - 400, rearranging we have:

1.5 * Y = 100

Y = 100 / 1.5 = 66.7, it would be approximately 66 roses.

Replacing the value of Y now in (1) we have:

2 * X + 1.5 * 66.7 = 400

2 * X + 99.9 = 400

X = (400-99.9) / 2 = 150.05, would be approximately 150 daisies.

We replace in (1) and (2) to check:

2 * 150 + 1.5 * 66 = 399, is the maximum we can spend because one more flower would be spent.

2 * 150 + 3 * 66 = 498, is the maximum we can spend because one more flower would be spent.

Therefore it meets Martha's requirements for his garden, 150 daisies and 66 roses.

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A delivery truck is stocked with boxes of leather footballs. The graph shows the relationship between the number of footballs an
pashok25 [27]

Answer:

21

Step-by-step explanation:

To find the answer, you'd have to continue tracing the diagonal line until it intersects with the vertical line that corresponds to the number 3.

If you do that, you'll see that in3 boxes, there are 21 footbals.


You can also calculate it mathematically:

If you have 7 balls per box as shown in the graph, you just have to multiply 7 by 3 to know how many balls you'll find in 3 boxes. 7 * 3 = 21.



Hope it helped,



BioTeacher101

6 0
2 years ago
Read 2 more answers
How many pounds of water must be evaporated from 50 pounds of a 3% salt solution so that the the remaining solution will be 5 %
svlad2 [7]

Answer:

Step-by-step explanation:

This is kinda tricky, but not nearly as bad as d = rt problems. Those are a nightmare!

We will make a table for this:

                         #lbs solution           *          % salt         =           lbs. salt

  3% solution

-  <u>Water                                                                                                      </u>

New solution

And we will now fill in what we know. The 3% solution part is easy. The number of pounds of that is 50 and the percent salt in 3% salt is....well, 3%. As a decimal, it is .03:

                             #lbs solution        *        %salt        =        lbs salt

  3% solution                50                 *          .03         =           1.5

-  <u>Water                                                                                                 </u>

New solution

The last column there with a 1.5 in it is the product of 50 times .03, since that is what the formula at the top of the table tells us we have to use. Now for the water. That's easy, too, since the amount of water we are evaporating (notice the subtraction sign out front of the word "water"; that indicates we are removing water) is our unknown, and we also know that water has 0% salt in it:

                          #lbs solution         *       %salt        =        lbs. salt

   3% solution            50                  *         .03         =           1.5

-   <u>Water                       x                  *            0          =            0         </u>

New solution

Now all we have left is the new solution row and the equation. Finding the equation from a mixture table is as easy as it can be! Super easy!

The new solution will be 50 - x since, going down column 1, we are subtracting the water from the 3% solution, the % salt is to be 5%:

                            #lbs. solution        *       %salt        =        lbs. salt

   3% solution               50                *         .03          =           1.5

-   <u>Water                          x                 *           0           =            0         </u>

New solution         50 - x                  *         .05          =     2.5 - .05x

Now we're ready for our equation. I got the 2.5 - .05x from multiplying

.05(50 - x), just so you know.

if we had to subtract the water from the salt solution and set it equal to the new solution in the first column, we also have to do it in the third column:

1.5 - 0 = 2.5 - .05x and solve for x:

-1 = -.05x so

x = 20 pounds of water

4 0
2 years ago
Select the graph of the solution. Click until the correct graph appears.<br><br> |x| + 3 &gt; 7
JulijaS [17]

Answer:

Graph 3.

Step-by-step explanation:

|x| + 3 > 7

|x| > 4

This means x > 4 or x < -4,

which is the third graph.

5 0
2 years ago
Read 2 more answers
Trees in urban areas help keep air fresh by absorbing carbon dioxide. A city has $2100 to spend on planting spruce and maple tre
insens350 [35]
Let x =  the number of spruce trees
Let y =  the number of maple trees

The information given is summarized in the following table.
Number  Cost/tree  Area used   CO₂ absorption
-----------   -------------   ---------------  ----------------------
      x         $30           600 ft²         650 lb/yr
      y         $40           900 ft²         300 lb/yr

The amount available to spend is $2100, therefore
30x + 40y ≤ 2100
or
(3/4)x + y ≤ 52.5                (1)

The land available for planting is 45,000 ft², therefore
600x + 900y ≤ 45000
or
(2/3)x + y ≤ 50                    (2)
     
The amount of CO₂ removed per year is
A = 650x + 300y               (3)

The shaded area in the graph shown below is the solution region.
Optimum values of A occur at the vertices, as shown.
The maximum removal rate occurs at (70, 3.33) at a rate of 46,500 lb/year.
Because we should have an integral number of trees, we should have
70 spruce and 3 maple trees.

Answer: 70  spruce, 3 maple

3 0
2 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
kifflom [539]

Looks like we have

\vec F(x,y,z)=z^2x\,\vec\imath+\left(\dfrac{y^3}3+\sin z\right)\,\vec\jmath+(x^2z+y^2)\,\vec k

which has divergence

\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(z^2x)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial z}=z^2+y^2+x^2

By the divergence theorem, the integral of \vec F across S is equal to the integral of \nabla\cdot\vec F over R, where R is the region enclosed by S. Of course, S is not a closed surface, but we can make it so by closing off the hemisphere S by attaching it to the disk x^2+y^2\le1 (call it D) so that R has boundary S\cup D.

Then by the divergence theorem,

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(x^2+y^2+z^2)\,\mathrm dV

Compute the integral in spherical coordinates, setting

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

so that the integral is

\displaystyle\iiint_R(x^2+y^2+z^2)\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^1\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{2\pi}5

The integral of \vec F across S\cup D is equal to the integral of \vec F across S plus the integral across D (without outward orientation, so that

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\iint_D\vec F\cdot\mathrm d\vec S

Parameterize D by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi. Take the normal vector to D to be

\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=-u\,\vec k

Then we have

\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^1\left(\frac{u^3}3\sin^3v\,\vec\jmath+u^2\sin^2v\,\vec k\right)\times(-u\,\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{2\pi}\int_0^1u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac\pi4

Finally,

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\left(-\frac\pi4\right)=\boxed{\frac{13\pi}{20}}

6 0
2 years ago
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