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swat32
2 years ago
6

Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh

en he starts his shift, the water level shows 4 gallons, or 128 cups of water. As the shift progresses, he records the level of the water every 10 minutes. After 2 hours, he uses a regression calculator to compute an equation for the decrease in water. His equation is W –0.414t + 129.549, where t is the number of minutes and W is the level of water. According to the equation, after about how many minutes would the water level be less than or equal to 64 cups?
150 minutes
160 minutes
170 minutes
180 minutes
Mathematics
1 answer:
sertanlavr [38]2 years ago
8 0
The Answer is 160 minutes

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1 year ago
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.11.
Elis [28]

Answer:

124.67cm³

Step-by-step explanation:

==>Given:

Dimensions of current can:

Height (h) = 12cm

Diameter = 6cm (radius = 3cm)

Volume of current can (V1) = 339.12 cm³

Dimensions of future cans to be increased multiple of 1.11:

height = 12cm × 1.11 = 13.32 cm

radius = 3cm × 1.11 = 3.33 cm

Volume of future can (V2) = πr²h = 3.14*3.33²*13.32

= 3.14*11.0889*13.32 = 463.791025

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5 0
2 years ago
ΔABC is dilated using a scale factor of 12 to produce ΔA'B'C'. Select all of the statements that apply to the transformation.
GalinKa [24]

Answer:

Options (3) and (6)

Step-by-step explanation:

ΔABC is a dilated using a scale factor of \frac{1}{2} to produce image triangle ΔA'B'C'.

Since, dilation is a rigid transformation,

Angles of both the triangles will be unchanged or congruent.

m∠A = m∠A' and m∠B = m∠B'

Since, sides of ΔA'B'C' = \frac{1}{2} of the sides of ΔABC

Area of ΔA'B'C' = \frac{1}{2}(\text{Area of triangle ABC})

Area of ΔABC > Area of ΔA'B'C'

Since, angles of ΔABC and ΔA'B'C' are congruent, both the triangles will be similar.

ΔABC ~ ΔA'B'C'

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3 0
1 year ago
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ddd [48]
825. That is what 0.825 represents.


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3 0
2 years ago
Read 2 more answers
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Darina [25.2K]

Answer:

Total cost for tiles and paints is $924.  

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

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Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

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Therefore, the total painting cost is $564.  

Tiles will be required for floor. Let us find the area of floor.

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Given: 1m squared floor tiles costs $3. So,  

\text{Total cost for tiles} = 3*120 = 360

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

\text{Combined total cost}= 564+360 = 924

Therefore, the combined total cost of tiles and paint is $924.

6 0
2 years ago
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