Answer:
- Benito's error was using the equal sign (=) instead of the congruency symbol (≅).
Explanation:
Benito's error was using the equal sign (=) instead of the congruency symbol (≅).
The congruency symbol (≅) means that the elements (segments, angles or figures in general) have the same measure, i.e. they have equal lengths for the segments or equal measure for the angles.
For instance, it is an error saying that the segment AB is equal to the segment BC because, as you clearly see in the picture, they are not same; they have the same length but they are joining different points, that makes them different in essence, although they have the same length. They would be equal only if they are the same figure.
In mathematics, you must not say that two different segments or two different angles are equal but they are congruent, which means that their lengths are equal. The use of equal is reserved for numbers and variables, not for figures like segment, points, angles, polygons.
2485.97 would be what he earned as an interest rate. The percentage would be6%
Answer:
jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8
Step-by-step explanation:
From the graph we can see that there is a whole in the graph at x=-2.
This is referred to as a point discontinuity.
Similarly, there is point discontinuity at x=8.
We can see that both one sided limits at these points are equal but the function is not defined at these points.
At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.
First of all, a bit of theory: since the area of a square is given by
where s is the length of the square. So, if we invert this function we have
.
Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by
So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}
<u>Answer:</u>
The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.
<u>Solution:</u>
Given, expression is 
We have to solve the above expression using change of base formula which is given as
Now, let us first apply logarithm for the given expression.
Then given expression turns into as, 
By using change of base formula,
x + 2 = 2.4649
x = 2.4649 – 2 = 0.4649
Hence, the value of x is 0.465 approximately and second option is correct one.
