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1 year ago

What is 528−−√+63−−√528+63 in simplest radical form?

Mathematics

2 answers:

Montano1993 [528]1 year ago

6 0

Answer: $13\sqrt{7}$

Step-by-step explanation:

In the simple radical form there are no square root is remain to find.

Since, the given expression,

$5\sqrt{28} + \sqrt{63}$

$5\sqrt{4\times 7} + \sqrt{9\times 7}$

$5\sqrt{4} \times \sqrt{7} + \sqrt{9}\times \sqrt{7}$

$5\times 2 \times \sqrt{7} + 3\times \sqrt{7}$

$10 \sqrt{7} + 3\sqrt{7}$

$(10 + 3)\sqrt{7}$

$13\sqrt{7}$

Since, we do not need to find further square root of 7.

Thus, the required radical form of $5\sqrt{28} + \sqrt{63}$ is $13\sqrt{7}$ .

Rufina [12.5K]1 year ago

3 0

Answer:

$13\sqrt{7}$

Step-by-step explanation:

$5\sqrt{28} +\sqrt{63}$

To simplify the given expression we simplify each radical

$5\sqrt{28} = 5\sqrt{4*7} = 5*2\sqrt{7} =10\sqrt{7}$

$\sqrt{63} = \sqrt{9*7} =3\sqrt{7}$

$5\sqrt{28} +\sqrt{63}$

$10\sqrt{7}+3\sqrt{7}$

$13\sqrt{7}$

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