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anygoal [31]
2 years ago
14

Mr Hughes is competing in the Mr. Legs campaign to raise money for the coral shores high school scholarship fund. On the first d

ay he collected $2. On the third day he collected $8 dollars. Let D represent each collection day and N represent the number of dollars collected on that day. Matt says claims the situation can be modeled by an exponential function. Emily disagrees and claims the number of dollars collected can be modeled by a linear function. Which statement is true about the number of dollars predicted to be collected on the 6th day based on the two models.
Mathematics
2 answers:
frosja888 [35]2 years ago
7 0

Answer:

B

Step-by-step explanation:

The answer is B i'm pretty sure

lakkis [162]2 years ago
4 0
<span>The number of dollars collected can be modelled by both a linear model and an exponential model. To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8) The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3 y - 2 = 3(x - 1) = 3x - 3 y = 3x - 3 + 2 = 3x - 1 Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17 To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2. 8 = 2r^(3 - 1) = 2r^2 r^2 = 8/2 = 4 r = sqrt(4) = 2 Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
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Answer:

£1.6

Step-by-step explanation:

£20 ÷ £2.3= 8 remainder 1.6

change= £1.6

6 0
2 years ago
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Students are going through a three-step process to obtain their ID cards. Each student will spend 2 minutes at the registration
kondaur [170]

Answer:

C. 160 minutes

Step-by-step explanation:

The calculation to be made will be to process 20 students

We have, according to the exercise, the following data:

For process 1: Registration table, Number of servers = 1, Time spent = 2 minutes

For process 2: cashier, number of servers = 3, time spent = 10 minutes

For process 3: ID processing station, number of servers = 4, time spent = 20 minutes

Demand rate = 0.125

To solve it, we will look for the capacity that the server has of the previously mentioned processes, calculating the following:

Capacity = Number of students served per minute

We can say that at the registration table we observe:

Time needed to serve 1 student = 2 minutes

Capacity = 0.5 students per minute

With the cashier we analyze the following:

Time needed to serve 1 student = 10 minutes

Number of servers = 3

Capacity = 0.3 students per minute

ID processing station

Time needed to serve 1 student = 20 minutes

Number of servers = 4

Capacity = 0.2 students per minute

When comparing the processes, it is definitely found that the bottleneck is the ID processing station, where it takes more time to serve a student, which leads us to infer that the capacity of the process is comparable to the capacity of the process bottleneck

Process capacity = 0.2 students per minute

Given, demand rate = 0.125 students per minute

We observe that the demand rate is less than the capacity of the process, therefore we can infer that the number of students served during each minute is the same as the demand rate.

In this way we find that:

Number of students served per minute = 0.125

Time needed to serve 1 student = 1 / 0.125 = 8 minutes

Time needed to serve 20 students = 8 x 20 = 160 minutes.

We conclude that the answer is that it will take 160 minutes to serve 20 students.

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2 years ago
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The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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