Question

Iliana multiplied 3p – 7 and 2p2 – 3p – 4. Her work is shown in the table. The expression (3 p minus 7)(2 p squared minus 3 p minus 4) is shown above a table with 3 columns and 2 rows. First column is labeled 2 p squared, second column is labeled negative 3 p, the third column is labeled negative 4. First row is labeled 3 p with entries 6 p cubed, negative 9 p squared, negative 12 p. Second row is labeled negative 7 with entries negative 14 p squared, 21 p, 28. Which is the product? 6p3 + 23p2 + 9p + 28 6p3 – 23p2 – 9p + 28 6p3 – 23p2 + 9p + 28 6p3 + 23p2 – 9p + 28

Answer 1

Answer:

the answer is C

Step-by-step explanation:

Answer 2

Answer:

The correct option is C) $6p^3-23p^2+9p+28$

Step-by-step explanation:

Consider the provided expression.

$3p - 7$ and $2p^2 - 3p - 4$

According to the provided information the table will be like this.

         $2p^2$     -3p        -4

3p     $6p^3$     -9p²      -12p

-7  $-14p^2$       21 p       28

The above table shows the terms after multiplication.

To find the product you just need to add the terms as shown.

$6p^3-9p^2-12p-14p^2+21p+28$

$6p^3-9p^2-14p^2-12p+21p+28$

$6p^3-23p^2+9p+28$

Hence, the product is $6p^3-23p^2+9p+28$.

You can verify this by product as shown.

$3p-7(2p^2-3p -4)$

$6p^3-9p^2-12p-14p^2+21p+28$

$6p^3-23p^2+9p+28$

Hence, the correct option is C) $6p^3-23p^2+9p+28$