Answer:
a) mt = -2
b) y=2-2x
Step-by-step explanation:
We have 
⇒ 
and we must find
a) The slope of the tangent line to the curve at the point (1,0)
b) The equation of the tangent line in part (a)
a) with the point (1,0) then f'(x) 
the slope (mt) in x=1 is
f'(1)=
, m t= -2
b) mt=-2 at the point (1,0), knowing that the pending point model is:
, we solve y-0 = -2(x-1) ⇒ y=-2x+2
Answer:
q1=11
q3= 33
Step-by-step explanation:
The data set has 44 number of students. The first quartile is 25 % of the numbers in the data set . So
25 % of 44 = 25/100 * 44= 0.25 *44 = 11
So the first quartile lies at 11.
Similarly the third quartile lies at the 75 % of the numbers of the data set . So
75 % of 44 = 75/100 * 44= 0.75 *44 = 33
So the third quartile lies at 33.
Answer:
x + 2y = 8.
Step-by-step explanation:
Line goes through (-4, 0) and (4, -4).
The slope is (-4 - 0) / (4 - -4) = -4 / (4 + 4) = -4 / 8 = -1/2.
Since we are looking for the equation of the line parallel to that line, the slope will be the same.
We have an equation of y = -1/2x + b. We have a point at (2, 3). We can then say that y = 3 when x = 2.
3 = (-1/2) * 2 + b
b - 1 = 3
b = 4.
So, we have y = -1/2x + 4.
1/2x + y = 4
x + 2y = 8.
Hope this helps!
