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White raven [17]
2 years ago
13

Find the vertex, focus, directrix, and focal width of the parabola. x2 = 20y

Mathematics
2 answers:
Lana71 [14]2 years ago
5 0

Answer:

Directrix is line with equation y=-5 and focus is the point with coordinates (0,5) with vertex (0,0) and focal width 20 units.

Step-by-step explanation:

Given the equation of parabola i.e

x^2=20y

we have to find the vertex, focus, directrix, and focal width of the parabola.  

Parabola:  x^2=20y

\text{standard equation of parabola}x^2=4by

Comparing, we get

4b=20 ⇒ b=\frac{20}{4}=5

Vertex: (0,0)

Focus: (0,b)=(0,5)

Directrix: y=-b ⇒ y=-5

Focal width:  4(5) = 20 units

Directrix is line with equation y=-5 and focus is the point with coordinates (0,5) with vertex (0,0) and focal width 20 units.

sp2606 [1]2 years ago
4 0
The parabola :
x² = 20 y
It is in the standard form : x² = 4 b y
b = 20 : 4 = 5
Vertex : ( 0, 0 );
Focus : <span>( 0,</span> 5 );
Directrix :  y + 5 = 0;  y = - 5
Focal width:  4 * 5  = 20 units
Answer: A )
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Two boats depart from a port located at (–10, 0) in a coordinate system measured in kilometers, and they travel in a positive x-
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To get the points at which the two boats meet we need to find the equations that model their movement:
Boat A:
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A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th
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Answer:

a

   The  90%  confidence interval is  52561.13  <  \mu  < 57540.8

b

Confidence interval for the population men between <u>$52561.13</u>  up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 25

     The  sample mean is  \= x  =  \$ 55,051

     The standard deviation is  \sigma  =  \$ 7,568

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             \alpha  =  100 -90

              \alpha  = 10\%

             \alpha  = 0.10

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table the values is  

               Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically  represented as

               E =  Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }

substituting values

               E =  1.645 * \frac{ 7568}{ \sqrt{ 25} }

             E =  2489.9

The 90% confidence interval is mathematically evaluated as

       \= x  -E  <  \mu  <  \= x  +E

substituting values

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