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Jet001 [13]
1 year ago
14

Ana can swim at a rate of 3/8 mile in 1/3 hour how many minutes would it take her to swim 1 mile at this rate round your answer

to the nearest Minute
Mathematics
1 answer:
slavikrds [6]1 year ago
7 0
ANSWER: 53 minutes


First, find what 1/3 of an hour equals in minutes. 20 minutes = 1/3 hour

Second, the goal is to find how many minutes it takes Ana to swim 1 mile, so you want to find how long it takes Ana to swim 1/8 of a mile.
3/8 mile = 20 minutes
20/3 = 6.666... so 1/8 mile = 6.666... minutes

Third, multiply the amount of time it takes to swim 1/8 mile by 8.
6.666 x 8 = 53.328 ⬅️ round to the nearest minute = 53 minutes
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Peter decided to buy a new car. He made a $2,160 down payment and then took a 48-month loan. The total amount for the car, plus
slava [35]
16560-2160=14400, 14400=48x, x=$300
3 0
2 years ago
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In which set do all of the values make the inequality 2x - 1 < 10 true?
igomit [66]

2x - 1 < 10\Leftrightarrow 2x < 11\Leftrightarrow x <  \frac{11}{2}

8 0
2 years ago
Hi. Please I need help with this :
ki77a [65]

Answer:

1.79553

Step-by-step explanation:

Step 1: Write expression

log₁₀(√(69.5² - 30.5²))

Step 2: Evaluate square root

log(√(4830.25 - 930.25))

log(√3900)

log(62.45)

Step 3: Find log

log₁₀ (or log)

log(62.45) = 1.79553

-------------------------------------

To use the table method. we find values that are easily evaluated by log₁₀

log₁₀(10) = 1

log₁₀(50) = 1.69897

log₁₀(100) = 2

So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.

3 0
2 years ago
the distribution of scores on a recent test closely followed a normal distribution wotb a mean of 22 and a standard deviation of
soldi70 [24.7K]

Answer:

1) 22.66%

2) 20

Step-by-step explanation:

The scores of a test are normally distributed.

Mean of the test scores = u = 22

Standard Deviation = \sigma = 4

Part 1) Proportion of students who scored atleast 25 points

Since, the test scores are normally distributed we can use z scores to find this proportion.

We need to find proportion of students with atleast 25 scores. In other words we can write, we have to find:

P(X ≥ 25)

We can convert this value to z score and use z table to find the required proportion.

The formula to calculate the z score is:

z=\frac{x-u}{\sigma}

Using the values, we get:

z=\frac{25-22}{4}=0.75

So,

P(X ≥ 25) is equivalent to P(z ≥ 0.75)

Using the z table we can find the probability of z score being greater than or equal to 0.75, which comes out to be 0.2266

Since,

P(X ≥ 25) = P(z ≥ 0.75), we can conclude:

The proportion of students with atleast 25 points on the test is 0.2266 or 22.66%

Part 2) 31st percentile of the test scores

31st percentile means 31%(0.31) of the students have scores less than this value.

This question can also be done using z score. We can find the z score representing the 31st percentile for a normal distribution and then convert that z score to equivalent test score.

Using the z table, the z score for 31st percentile comes out to be:

z = -0.496

Now, we have the z scores, we can use this in the formula to calculate the value of x, the equivalent points on the test scores.

Using the values, we get:

-0.496=\frac{x-22}{4}\\\\ x=4(-0.496) + 22\\\\ x=20.02\\\\ x \approx 20

Thus, a test score of 20 represent the 31st percentile of the distribution.

3 0
2 years ago
The table below gives the dimensions of a bridge and a scale model of the bridgeFind the scale factor of the model to the real b
Oksana_A [137]
The corresponding sides of the model and the actual bridge are in proportion because the two solids are similar.

The scale factor from the model to the actual bridge is 5/25 = 6/30 = 8/40 = 1/5.

Answer:  1/5
3 0
2 years ago
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