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2 years ago

How How many solutions does the nonlinear system of equations graphed below have?

1 answer:

4 0

Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations.

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Round 0.9998 to 3 decimal places

mojhsa [17]

The answer would be one because .9998 would round the 9 to a 10 which would round the second 9 and then the third nine to make 1

3 0

1 year ago

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Melinda works at a cafe. Each day that she works, she records x, the total dollar amount of her customers’ bills and then y, her

Anna35 [415]

Answer:

$26

Step-by-step explanation:

In the picture attached, the table, the plot and the line of best fit are shown. There we can see the next equation:

y = 0.177x + 25.936

where x is the total dollar amount of her customers’ bills and then y is her total daily wages.

This means that even if she serves no customers (x = 0) she will earn $26 ($25.936 rounded to the nearest dollar) for each day of work.

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2 years ago

Which is a solution to the equation? (x −2)(x + 5) = 18 x = −10 x = −7 x = −4 x = −2

Leona [35]

Answer:

Solutions:

$x=-7$

$x=4$

Step-by-step explanation:

$(x-2)(x + 5) = 18$

Expanding the factored form:

$x^2+5x-2x-10=18$

$x^2+3x-28=0$

Factoring the second-degree polynomial:

$(x+7)(x-4)=0$

This is true for

$x=-7 \text{ or } x=4$

4 0

2 years ago

PI-3.

Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

$x=2q_1+1$

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

$x=3q_2+1$

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

$x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1$

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

$x=7q_6$

This means $x-1$ is divisible by 2, 3, 4, 5 and 6 without remainder, so

$x-1=2\cdot 3\cdot 2\cdot 5n=60n$

Hence,

$x=60n+1, \ n\in N$

The smallest amount of money they could have raised is $301, because

$x=60\cdot 5+1=301$ is divisible by 7.

Now, the number $x=60n+1$ should be divisible by 7 and must be greater than 500.

So,

$60n+1>500\\ \\60n>499\\ \\n>8$

When n = 9,

$x=60\cdot 9+1=541$ is not divisible by 7.

When n = 10,

$x=60\cdot 10+1=601$ is not divisible by 7.

When n = 11,

$x=60\cdot 11+1=661$ is not divisible by 7.

When n = 12,

$x=60\cdot 12+1=721$ is divisible by 7.

B. The least amount of money they could have raised is $721

7 0

2 years ago

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The average cost of gas where you live is $3.50 per gallon, you are trying to decide whether to buy a hybrid or standard car. Th

Paladinen [302]

Answer:

Step-by-step explanation:

6 0

2 years ago

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