Answer:
t= 12.9 years
Step-by-step explanation:
Value after t years = initial value ( 1 - r )^t
Where,
Value after t years= $5000
Initial value = $22,400
r= depreciation rate = 11%
t= length of time (years)
Value after t years = initial value ( 1 - r )^t
5000 = 22,400 ( 1 - 0.11)^t
5000 = 22,400(0.89)^t
Divide both sides by 22,400
(0.89)^t = 5000 / 22,400
(0.89)^t = 0.2232
Take the log of both sides
t log 0.89 = log 0.2232
t= log 0.2232 / log 0.89
= -0.6513 / -0.0506
= 12.87
t= 12.9 years
Answer:
-7
Step-by-step explanation:
A constant number is a number that contains no variables like x and y. The only constant in that problem is -7.
Just multiply 42 by 10 and that gives you 420 , so the real car has a length of 420cm or 4.2 metres :)
Answer:
D
Step-by-step explanation:
You can plug in the given x and y values into the equations and see which one works for both of them.
D works for both of them:
5 = 5/4(4)
0 = 5/4(0)
Answer: C. Significant at 0.036
Step-by-step explanation:
Given:
Number of selected samples Ns= 500
Number of airplane that arrive on time Na = 482.
Number of airplane that arrive late Nl = 500 - 482 = 18
The probability that an airplane arrive late:
P(L) = Nl/Ns
P(L) = 18/500
P(L) = 0.036
Interpret an event as significant if its probability is less than or equal to 0.05.
Since P(L) < 0.05
P(L) = Significant at 0.036
