Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u> > <u>0.6-0.45)</u>
σ √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The output y is 
Explanation:
The expression is 
We need to determine the output y, when the value of input is x is 5.
That is, substituting
in
, we get,

Multiplying the value within the bracket, we have,

Subtracting the terms, we get,

Thus, the value of output y is 
Answer:
a). x = 11
b). m∠DMC = 39°
c). m∠MAD = 66°
d). m∠ADM = 36°
e). m∠ADC = 18°
Step-by-step explanation:
a). In the figure attached,
m∠AMC = 3x + 6
and m∠DMC = 6x - 49
Since "in-center" of a triangle is a points where the bisectors of internal angles meet.
Therefore, MC is the angle bisector of angle AMD.
and m∠AMC ≅ m∠DMC
3x + 6 = 8x - 49
8x - 3x = 49 + 6
5x = 55
x = 11
b). m∠DMC = 8x - 49
= (8 × 11) - 49
= 88 - 49
= 39°
c). m∠MAD = 2(m∠DAC)
= 2(30)°
= 60°
d). Since, m∠AMD + m∠ADM + m∠MAD = 180°
2(39)° + m∠ADM + 66° = 180°
78° + m∠ADM + 66° = 180°
m∠ADM = 180° - 144°
= 36°
e). m∠ADC = 
= 
= 18°
Answer:
y2 = (6x + 7)/36 + (Dx + E)e^x
Step-by-step explanation:
The method of reduction of order is applicable for second-order differential equations.
For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').
The differential equation becomes easy to solve, and all that is left are integration and substitutions.
Check attachments for the solution to this problem.
The answer to this question will be B