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Vlada [557]
1 year ago
5

The volume of a fish tank is given by the function V(x)=(x+7)(x-4)(x+3). Write a function describing a fish tank that has the sa

me height but is longer in length by 3 units and wider by 2 units.
Mathematics
1 answer:
Aleksandr [31]1 year ago
3 0

Answer:

V(x)=(x+9) * (x-4) * (x+6)

Step-by-step explanation:

A fish tank is normally in the shape of a rectangular prism. The volume of a rectangular prism can be calculated using the following formula

V = w * h * l

where w represents the width, h represents the heigh, l represents the length, and V represents the volume of the rectangular prism/fish tank. Therefore, we can use the function provided in the question and simply add 3 units to the length and 2 units to the width in order for it to work for our new fish tank.

V(x)=(x+9) * (x-4) * (x+6)

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Answer:

Step-by-step explanation:

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2 years ago
Select all of the following true statements if R = real numbers, Z = integers, and W = {0, 1, 2, ...}.
PSYCHO15rus [73]
We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).

W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
3 0
2 years ago
Read 2 more answers
A coordinate grid with 2 lines. The first line is labeled y equals 0.5 x plus 3.5 and passes through (negative 3, 1), (negative
Gelneren [198K]

Answer:

d

Step-by-step explanation:

3 0
2 years ago
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Lian invested an amount of money at an interest rate of 5.2% per year.
Zigmanuir [339]

Answer:

$6500

Step-by-step explanation:

Let the amount of money invested by Lian be $x

Interest rate = 5.2% per year

interest earned in first year will be  5.2% of  amount of money invested by Lian .

(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )

interest earned in one year if money invested by Lian is $x

= 5.2% of $x  (1)

But , it is given in one year  she received interest of 338 dollars

so, 338 dollars must be equal to 5.2% of $x

equating $338 with  5.2% of $x  , we have

5.2% of x  = 338

=> (5.2/100) * x = 338

=>5.2 x = 338*100

=> x = 33800/5.2 = 6500.

Thus,  amount of money Lian invested is $6500.

7 0
1 year ago
Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t
SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be h meters and h= h_1+h_s.

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ.                                        In ΔSPR.

⇒ tan(60) = \frac{h_1}{x} ...equation (i)        ⇒ tan (30)=\frac{h_1}{x+50}  ...equation (ii)

Dividing equation (i) and (ii)

⇒ \frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}

⇒ 3 = \frac{x+50}{x}

⇒ 3x=x+50

⇒ 3x-x=50

⇒ 2x=50

⇒ x=\frac{50}{2}

⇒ x=25 meters

To find h_1 plugging x=25 in equation (i)

⇒ h_1=x\times tan(60)

⇒ h_1=25\times 1.73

⇒ h_1=43.25 meters

The height of the cliff from ground :

⇒ h= h_1+h_s

⇒ h= 43.25+1.8

⇒ h=45.05 meters

The cliff is 45 m tall to the nearest meter.

8 0
2 years ago
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