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2 years ago

How would you shade a model to show ten thousandths?

1 answer:

3 0

Theres not really a way to show that on here unless i draw you a picture...you must know that 10 thousandths is equal to 1 hundredth. if you draw a 100 by 100 centimeter square on graph paper it will consist of a thousand squares since 100 x 100 is 1000, and if you colored in 10 of those squares, it would be 10 thousandths

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The 230 people at a party decide to order pizza for a snack. If each pizza has 8 slices, how many pizzas should they order so th

Nat2105 [25]

$230 : 8=28.75 \approx 29 \\ \\ the \ answer \ is \ variant\ D$

6 0

2 years ago

Read 2 more answers

At a desert resort, the temperature at 7 a.m. was 3°C. The temperature increased by an average of 3.4°C each hour until it reach

11Alexandr11 [23.1K]

Answer: It will take 8 hours to reach this temperature.

Step-by-step explanation:

Given: At a desert resort, the temperature at 7 a.m. was 3°C.

The temperature increased by an average of 3.4°C each hour until it reached 30.2°C.

Let x be the number of hours taken to reach 30.2°C..

As per given ,

Initial temperature +(average increase in temperature) (Number of hours) = 30.2

⇒3+3.4x=30.2

⇒3.4x=30.2-3

⇒3.4x=27.2

⇒ x=8 [Divide both sides by 3.4]

Hence, it will take 8 hours to reach this temperature.

6 0

1 year ago

m∠RSW = 2x + 16; m∠WSV = 3x + 2 m∠UST = 2x; m∠VSU = m∠UST Find m∠WSV. please answer this geotemrty is really hard

stepladder [879]

Answer: 56 degree

Explanation:

2x + 16 + 3x + 2 + 2x + 2x = 180 (straight angle)

9x + 18 = 180
9x = 162
x = 162/9
x = 18

But WSV = 3x + 2

And x = 18

=> 3(18) + 2
=> 54 + 2 = 56

8 0

2 years ago

The function D(t) defines a traveler's distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarge

nalin [4]

- At 2 hours, the traveler is 725 miles from home.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE.

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE.

Step-by-step explanation:

The function D(t) is defined as follows:

$D(t) = 300t+125$ for $t< 2.5$

$D(t) = 880$ for $2.5 \leq 3.5$

$D(t) = 75t+612.5$ for $t\leq 6$

Where

t is the time in hours

D(t) is the distance covered, in miles, after t hours

Now let's analyze the different statements:

- The starting distance, at 0 hours, is 300 miles. --> FALSE. In fact, if we substitute t = 0 into the 1st equation, we get

$D(0) = (300)(0)+125 = 125$

So, the distance at t = 0 is 125 miles.

- At 2 hours, the traveler is 725 miles from home. --> TRUE. In fact, if we substitute t = 2 into the 1st equation,

$D(2) = (300)(2)+125 = 725$

- At 2.5 hours, the traveler is 875 miles from home. --> FALSE. In fact, for t=2.5 we have to use the 2nd equation, which states that the distance is:

D(t) = 880

So, not 875 miles.

- At 3 hours, the distance is constant, at 880 miles. --> TRUE. This is clearly visible from the 2nd equation: for t between 2.5 and 3.5 (so, in this case), the distance is

D(t) = 880

- The total distance from home after 6 hours is 1,062.5 miles --> TRUE. In fact, if we replace t = 6 into the last equation,

$D(6)) = 75(6)+612.5=1062.5$

Learn more about functions:

brainly.com/question/3511750

brainly.com/question/8243712

brainly.com/question/8307968

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

4 0

1 year ago

Read 2 more answers

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

2 years ago