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gizmo_the_mogwai [7]
2 years ago
8

While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her

students answered question number 14 with multiple choice option B, while the other sixty percent answered A or C. Question #14 from Mrs. Jones's students' most recent quiz: 14) Solve the single variable equation for n. 3(-n + 4) + 5n = 2n n = 3 no solution infinitely many solutions Part 1: Use inverse operations and rules of equation solving to determine the correct answer to Mrs. Jones's quiz question number 14. Include all of your work in your final answer. Part 2: Use complete sentences to compare the similarities and differences of each of the multiple choice answer options A-C. In your answer, rationalize why a student would choose each of the options as the correct answer.
Mathematics
2 answers:
iris [78.8K]2 years ago
5 0

Answer:

no its has no solution

Step-by-step explanation:

astra-53 [7]2 years ago
4 0

Answer:

 

The correct answer was given: Brain

y = (x+5)(x+2)

step-by-step explanation:

we are given the following the quadratic function and we are to rewrite it in intercept or factored form:  

y = x^2 + 7x + 10  

we can factorize the given quadratic function such that when multiplied, the factors give a product of 10 and when added, they give a result of 7.

y=x^2+5x+2x+10

y=x(x+5)+2(x+5)

y=(x+5)(x+2)

therefore, the factored form of the given function is y = (x+5)(x+2)

Step-by-step explanation:

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“there are several approximations used for pi, including 3.14 and 22/7. pi is approximately 3.14159265358979..." a. label pi and
BlackZzzverrR [31]
Hello,

a) | |PA|-π |>| |PB|-π | (see pic)

c) 3.14< x/113 <=π <22/7

==>3.14*113<x<22/7 * 113
==>354.82 <x < 355.14285
==>x=355


Answer 355/113=3,1415929203539823008849557522124



6 0
2 years ago
Choose the option that best completes the statement below. In finding the number of permutations for a given number of items, __
vodomira [7]
Let’s look at the permutations of the letters “ABC.” We can write the letters in any of the following ways:
ABC
ACB
BAC
BCA
CBA
CAB
Since there are 3 choices for the first spot, two for the next and 1 for the last we end up with (3)(2)(1) = 6 permutations. Using the symbolism of permutations we have: 3 P_{3}=(3)(2)(1)=6. Note that the first 3 should also be small and low like the second one but I couldn’t get that to look right.

Now let’s see how this changes if the letters are AAB. Since the two As are identical, we end up with fewer permutations.
AAB
ABA
BAA
To make the point a bit better let’s think of one A are regular and one as bold A.
A
BA and ABA look different now because we used bold for one of the As but if we don’t do this we see that these are actual the same. If they represented a word they would be the same exact word.

So in this case the formula would be \frac{3 P_{3} }{2!}= \frac{(3)(2)(1)}{(2)(1)}= \frac{6}{2}=3. We use 2! In the denominator because there are 2 repeating letters. If there were three we would use 3!


Hopefully, this is enough to let you see that the answer is A. The number of permutations is limited by the number of items that are identical.



7 0
2 years ago
Estimate the value of 9.9 squared x 1.79
Helen [10]
9.9^2X1.79
9.9^2=98.01
98.01X1.79=175.4379
7 0
2 years ago
Read 2 more answers
A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl
Citrus2011 [14]

Answer:

a) 98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

b)   95% confidence interval for the standard deviation.

(214.91 , 441.53)

Step-by-step explanation:

Given a size of sample 'n' =14

given mean of the sample x⁻ = $664.14

standard deviation of the sample 'S' = $297.29.

a)

<u>98% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-}+ t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

The degrees of freedom γ=n-1 =14-1 =13

t₁₃ = 2.650 at 98% of confidence level of signification.

(664.14- 2.650\frac{297.29}{\sqrt{14} } , 664.14+ 2.650\frac{297.29}{\sqrt{14} } )

on calculation, we get

(664.14-210.553 , 664.14+210.553)

(453.586 , 874.693)

98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

<u>95% of confidence intervals</u>

({s\sqrt{\frac{n-1}{X^{2} _{(\frac{\alpha }{2} ,n-1) } } } ,s\sqrt{\frac{n-1}{X^2_{\frac{1-\alpha }{2},n-1 } } }  )

The degrees of freedom γ=n-1 =14-1 =13

X^2_{0.05,13} =22.36     (check table)

X^2_{0.95,13} = 5.892    (check table)

(297.29. (\sqrt{\frac{14-1}{X^2_{0.05,13}  } } ),297.29(\sqrt{\frac{14-1}{X^2_{0.95,13} } } )

(297.29. (\sqrt{\frac{14-1}{22.36  } } ),297.29(\sqrt{\frac{14-1}{5.892 } } )

(214.91 , 441.53)

95% confidence interval for the standard deviation.

(214.91 , 441.53)

7 0
2 years ago
Ray CE is the angle bisector of ACD. Which statement about the figure must be true? mECD = mECB mACE = mACD ACE DCB
Ainat [17]

Answer:

ACE = ECD is the answer

Step-by-step explanation:

5 0
2 years ago
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