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2 years ago

Explain how to draw a trend line for a scatterplot using the divide-center of data method.

Mathematics

2 answers:

inysia [295]2 years ago

7 0

Answer:

<em>Sample Answer: </em><em>To draw a trend line with the divide-center method, first exclude any outliers. Draw a vertical line to divide the data cluster into two groups with approximately the same number of points. Find the center of each group and connect those centers to form the trend line.</em>

Korvikt [17]2 years ago

6 0

Before you can draw a trend line in your data, you should have a given data at hand. And then draw the trend line or line of best fit.

1. Plot your data in a graphing paper or excel.
2. Make sure that your plotted data has a solid mark to indicate the points in the graph.
3. Divide your data points by labeling x at the center, at the farthest part of your line (left or right diagonally).
4. If you feel that the data are now finely divided, then construct a line base on the x marks you're placing
5. Then you will notice how far or near your date points are by simply looking at the points near the constructed line that you created.

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If you are a student with no assets of any value and have liability insurance on an old car that pays a maximum of $50,000 per a

svetoff [14.1K]

Answer:

Step-by-step explanation:

they will sue for the rest of the money, because they are entitled to it if you are the cause of an accident.

6 0

2 years ago

The probability that a person in the United States has type B+ blood is 12%. Three unrelated people in the United States are s

V125BC [204]

Answer:

The probability that all three have type B+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a person in the United States has type B+ blood is 12%.

This means that $p = 0.12$

Three unrelated people in the United States are selected at random.

This means that $n = 3$

Find the probability that all three have type B+ blood.

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728$

The probability that all three have type B+ blood is 0.001728

4 0

2 years ago

Which procedure justifies whether -3x(5-4)+3(x-6) is equivalent to -12x-6?

Diano4ka-milaya [45]

Answer:

x=1

Step-by-step explanation:

-3x(5-4)+3(x-6)

-15x+12x+3x-18

-3x+3x-18

-18=-12x-6

-12x=-18+6

-12x=-12

12x=12

x=12/12

x=1

4 0

1 year ago

Read 2 more answers

In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many

kompoz [17]

1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5

3 0

1 year ago

Read 2 more answers

How many hundreds flats are equal to 400 tens rods

vitfil [10]

40 hundreds flats. 400 tens = 4,000. 40 hundreds also equals 4,000.

4 0

1 year ago

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