Answer:
C is (-18, 24)
Scale factor --> 1 1/3
A is (9, - 4 1/2) *4 1/2 is also 4.5
<u><em>Brainliest please, I need a few more :D</em></u>

Since we have given that
Total number of tickets =10
Number of winning tickets =6

In which one out of every three awards is a large prize
so,

Now,


Answer:
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 22
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0739
The margin of error is:
M = T*s
In which s is the standard deviation of the sample.
In this question:
s = 3.
Then
M = 2.0739*3 = 6.22
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
K(-1+1.01)+0.03=-2.45-1.81k
0.01k+1.81k=-0.03-2.45
1.82k=-2.42
k=-2.45\1.82=1.3